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...n)!) = 10 ==> 120/(n!(5 - n)!) = 10 ==> n!(5 - n)!)/120 =

**1**/**10**==> n!(5 - n)! = 12. Since this will be only be...n â‰¤ 5. Checking the integers from 0 to 5,**inclusive**: n = 0 ==> 0!(5 - 0)! = 0! * 5! = 120 â‰ 12 n = 1 ==>...3 Answers Â· Science & Mathematics Â· 21/05/2010

...0; i<NUMBER; i++) { num = r.nextInt(10); // 0..9

**inclusive**intArr[i] = num; link.add(num); } // end for System.out.println...2 Answers Â· Computers & Internet Â· 17/09/2014

when you sat "Theists"

**do**you mean...... 1 Abrahamic religions 1.1 BÃ¡bism 1.2 BahÃ¡'Ã Faith 1.3 Christianity 1.3.1 Catholicism...5 Answers Â· Society & Culture Â· 21/05/2012

1) 3(tan^2 x)=10(secx-1) 3(sec^2 x -

**1**) =**10**(secx-1) 3sec^2 x - 3 = 10secx - 10 3sec^2 x -10secx -3+7 = 0 3sec^2 x -10secx +4...2 Answers Â· Science & Mathematics Â· 22/08/2010

...don't even need a calculator. All you need to

**do**is find critical numbers and substitute. y... because brackets indicate that they are**inclusive**.) -3: (-3)^4 -10(-3)^2 -**1**-**10**-sqrt(5) and sqrt(5): (...4 Answers Â· Science & Mathematics Â· 25/07/2011

...1 to 7) Ï€ âˆš[2(1+5x) + 1] dx = âˆ«(x = 1 to 7) Ï€ âˆš(10x + 3) dx = Ï€ * (2/3)(

**1**/**10**)(10x + 3)^(3/2) {for x = 1 to 7} = (Ï€/15) [73^(3/2) - 13^(3/2)]. --------------- 2...1 Answers Â· Science & Mathematics Â· 15/11/2012

...all be positive integers. All you need to

**do**is allow inputs for both players...**10**) #picks a random number between 1 and 10 (**inclusive**) x = abs(x - r) y = abs(y - r) if x == y...3 Answers Â· Computers & Internet Â· 31/08/2011

1...3....9 1=1 3-1=2 3=3 3+1=4 9-3-1=5 9-3=6 9-3+1=7 9-1=8 9=9 9+

**1**=**10**9+3-1=11 9+3=12 9+3+1=134 Answers Â· Education & Reference Â· 10/10/2008

... all of the digits by 5 and

**does**nothing else --- a statement easily verifiable with the above definition..., if any of a(k) is between 2 and 9**inclusive**, then notice that: 5a = 5a(**1**) +**10**[5a(2)] + 100[5a(3...3 Answers Â· Science & Mathematics Â· 27/12/2012

1.

**Do**you remember the identity, sin(a-b)=sin(a)cos(b)-cos(a)sin(b) So..., first of all, the interval can be simply put as (0,2pi)**inclusive**. So just solve when cos(x)=0. So that is when x=pi...2 Answers Â· Science & Mathematics Â· 18/06/2012

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