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  1. ...n)!) = 10 ==> 120/(n!(5 - n)!) = 10 ==> n!(5 - n)!)/120 = 1/10 ==> n!(5 - n)! = 12. Since this will be only be...n ≤ 5. Checking the integers from 0 to 5, inclusive: n = 0 ==> 0!(5 - 0)! = 0! * 5! = 120 ≠ 12 n = 1 ==>...

    3 Answers · Science & Mathematics · 21/05/2010

  2. ...0; i<NUMBER; i++) { num = r.nextInt(10); // 0..9 inclusive intArr[i] = num; link.add(num); } // end for System.out.println...

    2 Answers · Computers & Internet · 17/09/2014

  3. when you sat "Theists" do you mean...... 1 Abrahamic religions 1.1 Bábism 1.2 Bahá'í Faith 1.3 Christianity 1.3.1 Catholicism...

    5 Answers · Society & Culture · 21/05/2012

  4. 1) 3(tan^2 x)=10(secx-1) 3(sec^2 x -1) = 10(secx-1) 3sec^2 x - 3 = 10secx - 10 3sec^2 x -10secx -3+7 = 0 3sec^2 x -10secx +4...

    2 Answers · Science & Mathematics · 22/08/2010

  5. ...don't even need a calculator. All you need to do is find critical numbers and substitute. y... because brackets indicate that they are inclusive.) -3: (-3)^4 -10(-3)^2 -1 -10 -sqrt(5) and sqrt(5): (...

    4 Answers · Science & Mathematics · 25/07/2011

  6. ...1 to 7) π √[2(1+5x) + 1] dx = ∫(x = 1 to 7) π √(10x + 3) dx = π * (2/3)(1/10)(10x + 3)^(3/2) {for x = 1 to 7} = (π/15) [73^(3/2) - 13^(3/2)]. --------------- 2...

    1 Answers · Science & Mathematics · 15/11/2012

  7. ...all be positive integers. All you need to do is allow inputs for both players...10) #picks a random number between 1 and 10 (inclusive) x = abs(x - r) y = abs(y - r) if x == y...

    3 Answers · Computers & Internet · 31/08/2011

  8. 1...3....9 1=1 3-1=2 3=3 3+1=4 9-3-1=5 9-3=6 9-3+1=7 9-1=8 9=9 9+1=10 9+3-1=11 9+3=12 9+3+1=13

    4 Answers · Education & Reference · 10/10/2008

  9. ... all of the digits by 5 and does nothing else --- a statement easily verifiable with the above definition..., if any of a(k) is between 2 and 9 inclusive, then notice that: 5a = 5a(1) + 10[5a(2)] + 100[5a(3...

    3 Answers · Science & Mathematics · 27/12/2012

  10. 1. Do you remember the identity, sin(a-b)=sin(a)cos(b)-cos(a)sin(b) So..., first of all, the interval can be simply put as (0,2pi) inclusive. So just solve when cos(x)=0. So that is when x=pi...

    2 Answers · Science & Mathematics · 18/06/2012

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