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  1. ..., if arr has k elements they are indexed from 0 through k-1, inclusive. Let len be the length of the array, say 100. You can get those...

    2 Answers · Computers & Internet · 04/10/2012

  2. sorry, not going to do your homework for you... this is very easy to figure out too

    2 Answers · Computers & Internet · 31/10/2006

  3. ...; 10 || input_int > 20) { /* error occurred...odd */ } (You *can* do this without the if/else for even...set up a for loop to run through your values... the loop variable by 1, use i += 2. You can...

    3 Answers · Computers & Internet · 05/02/2010

  4. ...wid;//* } else if (wid < 1 || wid > 10) { height = hei; //* width = 3...for loop. You want it to loop through accordingly, and print out the pound symbol such...question is asking, you could do 3 loops. One loop for the...

    1 Answers · Computers & Internet · 22/03/2013

  5. ... between 1 and 6, inclusive. A better... is between 1 and 20. The best...and 1 and 6 is through remainders...this is really doing. The function rand...

    1 Answers · Computers & Internet · 08/02/2010

  6. ...+mouse wheel, or the view -> zoom menu. Then do a screenshot (Print Screen on your keyboard...indeed different sizes. On a side note, 10-110 inclusive is actually 101 sizes, not 100. You'...

    2 Answers · Computers & Internet · 21/01/2008

  7. ... namespace std; void main() { const int array_size = 20; int num[array_size], n; bool c; for (n=0; n<...i = 0; i < n; i++) { if(num[n] == num[i]) c = 1; } } if (c == 1) cout<<"...

    3 Answers · Computers & Internet · 24/11/2008

  8. ... can determine if position i % 64 of array[i/64] is 0 or 1 through the operation: array[i / 64] & (1 << (i%64)) What this does is it gets the value in position i%64 of array[i/64...

    3 Answers · Computers & Internet · 12/03/2013

  9. ... the first trip through the loop you get this: for item...item = list[indexB] = 20   if item == list...list[indexB] == list[1] == 20, True   ...]     ## does not execute   if item...

    3 Answers · Computers & Internet · 10/03/2011

  10. ...not yet visited. If it does, don't display it. See below... changed the array size from 20 to 5, for ease of testing. ...nbsp;       if ((i == N-1) || (search(&intArray[i + 1...

    1 Answers · Computers & Internet · 30/10/2010

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