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In the units position, the digits 1 through 9 appear 5 times. In the tens position, the digits 1 through 4 appear 10 times 5(1+2+3+...+9) + 10(1+2+3+4) = 5*45 + 100 = 345

...these in each hundred block left to be counted. Therefore we have 9*10 + 9*9 = 90 + 81 = 171. Since there are 900 numbers from 100 - 999 inclusive, the odds of picking one with a 0 in are: 171 / 900, D...

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...if the range was 10 through 11, the number is not 11-10=1, it is 11-10+1=2...the number 27 (10-36 inclusive), then the odds of...25 The question does not stipulate whether the ...

...distribute the 2. 4w+10+2w≤64 add the like terms. 6w+10≤64 subtract ten from both sides. 6w≤54 divide by 6 to isolate the variable. w≤9. ok now i did #1. ignore the 80 games part, it's only there to...

I know how to do #10 and #7. 10. Note that 23! = 21... the integer, adding 1 to the exponent on each prime factor, then... that in the numbers 1 through 21, there are 10 multiples...

1 D 2 A 3 B 4 D 5 D 6 D 7 B 8 B 9 B 10 D 11 D 12 A 13 C 14 C 15 D 16 D 17 B

... the numbers within the brackets. For example: (1, 10) means: 2, 3, 4, 5, 6, 7, 8, 9 So for your questions: 2 through 7 inclusive means: [2,7] the numbers 2 and 7 are part of the set