...7=1.8097x 10^-5T In the smaller loop, the radius = r1 = 12.5

**cm**= 0.125 m I1 = 3.6 Amp hence magneti field at the center = B1...1 Answers · Science & Mathematics · 14/05/2020

3.7 m/sec * (5.1

**cm**/ 2.3**cm**)^2 = exit speed1 Answers · Science & Mathematics · 05/05/2020

(a) conserve momentum: 4.5g * 26.8m/s + 0 = 4.5g * -13.4cm/s + 13.5g * v v = 13.4

**cm**/s (b) KE = ½ * 0.0135kg * (0.134m/s)² = 1.2x10^-4 J Hope this helps!1 Answers · Science & Mathematics · 09/05/2020

Hence, the image is formed behind the mirror and virtual erect and larger than the object. This mean is bigger and erect.

1 Answers · Science & Mathematics · 13/05/2020

Let's see if this works M1V1 + M2V2 = M1V3 + M2V4 taking right as the positive direction 21.4(56.8) + 10.7(14.2) = 21.4 V3 + 10.7(71) solve for V3 I get close to 28 m/s When you get a good response, please consider giving a...

1 Answers · Science & Mathematics · 09/05/2020

...2.00*d² This quadratic has a root at d = 0.245 m = 24.5

**cm**◄ our solution and d = 1.09 m ← outside the permitted range ...1 Answers · Science & Mathematics · 13/05/2020

... of Oil) = 1970 J/KgC density (olive oil) = 0.918 g/

**cm**^3 (Use to calculate mass) Lv (Latent Heat of ...3 Answers · Science & Mathematics · 12/05/2020

λ = v / f In the air: λ = 343m/s /(500/s) = 68.6

**cm**In the water: λ = 1450m/s /(500/s) = 2.90m.2 Answers · Science & Mathematics · 13/05/2020

Ooh, this looks kinda nasty. compression of spring at equilibrium point might come in handy: x₀ = mg / k = 1.31*9.81/302 m = 0.04255 m When the plank is displaced upwards by small angle Θ, the amplitude of oscillation will be x = (L/2)sinΘ - x₀...

1 Answers · Science & Mathematics · 12/05/2020

net torque on pulley τ = [4.0kg*(9.8m/s² - a) - M*(9.8m/s² + a)]*0.06m - 0.60N·m where M is the smaller mass. and τ = I*α [4.0kg*(9.8m/s² - a) - M*(9.8m/s² + a)]*0.06m - 0.60N·m = ½*1.9kg*(0.06m)² * α α...

3 Answers · Science & Mathematics · 01/05/2020

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