I assume that "10

**cm**size" means a perimeter of 10**cm**. The internal angles of...1*cos108º = 2.618**cm**² by the law of cosines c = 1.618**cm**so the semiperimeter is s = ½(1.618 + 1 + 1)**cm**= 1.809**cm**...2 Answers · Science & Mathematics · 18/09/2020

displacement = 20

**cm**- (- 20cm) + (- 10**cm**) = 30**cm**distance covered = |(-20cm) - (20cm)| + |(-10cm) - (-20**cm**)| = 40cm + 10cm = 50**cm**1 Answers · Science & Mathematics · 05/07/2020

a) at 14

**cm**, the "enclosed" charge is Q = 50nC * (14/30... * 5.08e-9C / (0.14m)² = 2331 N/C (outward) b) at 37**cm**, the enclosed charge is 50 nC: E = 8.99e9N·m²...1 Answers · Science & Mathematics · 30/09/2020

...7=1.8097x 10^-5T In the smaller loop, the radius = r1 = 12.5

**cm**= 0.125 m I1 = 3.6 Amp hence magneti field at the center = B1...1 Answers · Science & Mathematics · 14/05/2020

...)/(u₁+u₂) = (6.5*22 + 14*(-15))/(6.5 + 14) = -3.27

**cm**/s Initial vel. of 6.5g object in CoMF = 22 - (-3.27) = 25.27**cm**/s...1 Answers · Science & Mathematics · 18/06/2020

A=4.14

**cm**V=3.59 V=f*λ V/λ=(A*2*pi*f)/(f*I) 3.59=(2*A*pi)/I I=(2*4.14*pi)/3.59 I=7.241 Answers · Science & Mathematics · 08/07/2020

...v 1 / v = 1 / f - 1 / u 1 / v = 1 / 38 - 1 / 19 = (1 - 2) / 38 = - 1 / 38 v = - 38

**cm**The image distance is negative —> the image is virtual, ...1 Answers · Science & Mathematics · 19/11/2020

... / (πd²/4) = 4*1100

**cm**³/s / π(0.50**cm**)² = 5602**cm**/s = 560 m/s v = 4*1100**cm**³/s / π(2.0**cm**)² = 350**cm**/s = 35 m/s...1 Answers · Science & Mathematics · 20/10/2020

... mark at which the second mass is attached, ℓ

**cm**= 59.0**cm**2 Answers · Science & Mathematics · 12/07/2020

...283k = 1.01e5Pa * d³ / 293K solves to d = 0.89

**cm**Hope this helps!1 Answers · Science & Mathematics · 19/10/2020