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  1. ...283k = 1.01e5Pa * d³ / 293K solves to d = 0.89 cm Hope this helps!

    1 Answers · Science & Mathematics · 19/10/2020

  2. ...e) PS = PE      1.5 = 1.0(9.8)h        h = 0.15306... ≈ 15.3 cm f) 1.5 J   Spring potential has converted to gravity...

    1 Answers · Science & Mathematics · 18/10/2020

  3. .../C The inner loop appears to have a radius of 3.1 cm and the outer loop, 4.15 cm Taking "up out of the page" as positive...

    1 Answers · Science & Mathematics · 14/10/2020

  4. for rod at end, I = mL²/3 = M*(1.1m)²/3 = M*0.403m² torque τ = mg(L/2)cosΘ = M*9.8m/s²*(1.1m/2)*cos23º τ = M*4.96 m²/s² α = τ/I = M*4.96m²/s² / M*0...

    1 Answers · Science & Mathematics · 14/10/2020

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