a) at 14

**cm**, the "enclosed" charge is Q = 50nC * (14/30... * 5.08e-9C / (0.14m)² = 2331 N/C (outward) b) at 37**cm**, the enclosed charge is 50 nC: E = 8.99e9N·m²...1 Answers · Science & Mathematics · 30/09/2020

... / (πd²/4) = 4*1100

**cm**³/s / π(0.50**cm**)² = 5602**cm**/s = 560 m/s v = 4*1100**cm**³/s / π(2.0**cm**)² = 350**cm**/s = 35 m/s...1 Answers · Science & Mathematics · 20/10/2020

...283k = 1.01e5Pa * d³ / 293K solves to d = 0.89

**cm**Hope this helps!1 Answers · Science & Mathematics · 19/10/2020

apply the law of sine ..a................b ---------=-------------- .sin(A)........sin(B) ..45..............b --------- = ----------- .sin(70) ....sin(40) 45sin(40) = bsin(70) b = 30.78

**cm**or 31**cm**answer//2 Answers · Science & Mathematics · 06/10/2020

it is formed into two squares? basically, if z is one piece and y is the other z + y = x sides of each are z/4 and y/4 areas are z²/16 and y²/16 sum is z²/16 + y²/16 12(z/4) = y/4 12z = y x = z + y = z + 12z = 13z...

1 Answers · Science & Mathematics · 20/10/2020

(38

**cm**X 38**cm**x 24**cm**) = 34656**cm**^3 = 34.656 L n = PV / RT = (715 torr) x (34.656 L) / ((62...1 Answers · Science & Mathematics · 11/10/2020

...nothing truly paradigm shifting enough to be considered 'legendary'.

**CM**Punk: I think he will be, and I think in some circles...2 Answers · Sports · 28/09/2020

...quot; Here is how to reach that answer 1) First determine how many

**cm**are in 2300 km One km is equal to 100 000**cm**2300 km @ 100 000...2 Answers · Education & Reference · 16/10/2020

... O be the center of the circle. ∠BOC = 90° OB = 2

**cm**OC = 2**cm**Do you see where this is going? Consider...1 Answers · Science & Mathematics · 08/10/2020

The cool thing about radians is it directly matches to the distance along a unit circle, so just multiply the *radius* times the angular velocity. v = rω v = 6.15

**cm*** 5.2 rad/sec v = 31.98**cm**/sec Answer: ~32**cm**/sec3 Answers · Science & Mathematics · 26/10/2020