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A) (160.5*10^-9 g) / ((13.3

**cm**^3)*(1.00 g/**cm**^3)) = 12.067*10 ^-9 .. = 12.07 ppb B) (0.650 km^3)*((10^4 dm)/km)^3*(1 kg/dm^3)*(12.07*10^-9)= 7850 kg C) = (7,850 kg)*(2.61 days)/(42.6 kg) = 480 days or = 1.32 years1 Answers · Science & Mathematics · 01/10/2019

Density. Any substance with a density less than 1.00 g/

**cm**^3 will float. If the density is greater than 1.00 g/**cm**^3 then it will sink. .. Candles must have a density less than 1.005 Answers · Science & Mathematics · 17/09/2019

Put 1.6 mL buffer into 4 tubes. Add 0.4 mL of the original solution to the first tube. Mix. Remove 0.4 mL of that solution and transfer to the next tube. Mix. Remove 0.4 mL of that and add it to the third tube...

1 Answers · Science & Mathematics · 13/09/2019

...^-4 mol/L = 0.16 mM Absorbance = 82.1 mM^-1

**cm**^-1 (1**cm**) (0.16 mM) = 13.1 I assumed a 1**cm**path length for...1 Answers · Science & Mathematics · 13/09/2019

3X10^-6 mol/L X 0.250 L X 64,500 g/mol = 0.048 g = 48 mg

1 Answers · Science & Mathematics · 13/09/2019

...the circumference to determine the volume: (43.1 mm)^3) / (6 π^2) = 1352.01 mm^3 = 1.35201

**cm**^3 (12.1 g) / (1.35201**cm**^3) = 8.95 g/**cm**^3 [You didn't ask, but the...1 Answers · Science & Mathematics · 12/09/2019

(2.68 in)^3 × (2.54

**cm**/in)^3 × (4.50 g Ti/**cm**^3) / (47.867 g Ti/mol) × (6.022 × 10^23 atoms/mol) = 1.79 × 10^25 atoms Ti3 Answers · Science & Mathematics · 11/09/2019

...measurement. Suppose that they were the length and width given in

**cm**. NOW you can talk about uncertainty and significant digits. Now we...2 Answers · Science & Mathematics · 13/09/2019

They just have to be the same units although in this case, 1 g/mL = 1 g/

**cm**^31 Answers · Science & Mathematics · 08/09/2019

Yes you have set up correctly answer is 8,92 g/

**cm**^31 Answers · Science & Mathematics · 31/08/2019

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