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  1. A) (160.5*10^-9 g) / ((13.3 cm^3)*(1.00 g/cm^3)) = 12.067*10 ^-9 .. = 12.07 ppb B) (0.650 km^3)*((10^4 dm)/km)^3*(1 kg/dm^3)*(12.07*10^-9)= 7850 kg C) = (7,850 kg)*(2.61 days)/(42.6 kg) = 480 days or = 1.32 years

    1 Answers · Science & Mathematics · 01/10/2019

  2. Density. Any substance with a density less than 1.00 g/cm^3 will float. If the density is greater than 1.00 g/cm^3 then it will sink. .. Candles must have a density less than 1.00

    5 Answers · Science & Mathematics · 17/09/2019

  3. Put 1.6 mL buffer into 4 tubes. Add 0.4 mL of the original solution to the first tube. Mix. Remove 0.4 mL of that solution and transfer to the next tube. Mix. Remove 0.4 mL of that and add it to the third tube...

    1 Answers · Science & Mathematics · 13/09/2019

  4. ...^-4 mol/L = 0.16 mM Absorbance = 82.1 mM^-1 cm^-1 (1 cm) (0.16 mM) = 13.1 I assumed a 1 cm path length for...

    1 Answers · Science & Mathematics · 13/09/2019

  5. ...the circumference to determine the volume: (43.1 mm)^3) / (6 π^2) = 1352.01 mm^3 = 1.35201 cm^3 (12.1 g) / (1.35201 cm^3) = 8.95 g/cm^3 [You didn't ask, but the...

    1 Answers · Science & Mathematics · 12/09/2019

  6. (2.68 in)^3 × (2.54 cm/in)^3 × (4.50 g Ti/cm^3) / (47.867 g Ti/mol) × (6.022 × 10^23 atoms/mol) = 1.79 × 10^25 atoms Ti

    3 Answers · Science & Mathematics · 11/09/2019

  7. ...measurement. Suppose that they were the length and width given in cm. NOW you can talk about uncertainty and significant digits. Now we...

    2 Answers · Science & Mathematics · 13/09/2019

  8. They just have to be the same units although in this case, 1 g/mL = 1 g/cm^3

    1 Answers · Science & Mathematics · 08/09/2019

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