Yahoo Web Search

  1. Ads
    related to: Cm
  1. In the circumstance described the component of F perpendicular to the rod is 1/2 F In the second case the component is F ie F * x = 1/2 F * 40 cm -> x = 20 cm

    1 Answers · Science & Mathematics · 04/03/2021

  2. torque = Fd = 40 N •0.2 m = 8 Nm

    2 Answers · Science & Mathematics · 04/03/2021

  3. At ½ the maximum speed, it has ¼ of the maximum KE, which means it has 3/4 of the maxim PE, which means x = 4.37cm * √(3/4) = 3.78 cm

    1 Answers · Science & Mathematics · 04/03/2021

  4. Since it begins and ends "at rest," KE is not involved and the mass's GPE gets converted into spring SPE: mgh = ½kh² m/k = h / 2g = 0.0616m / 2*9.81m/s² = 0.00314 s² T = 2π√(m/k...

    2 Answers · Science & Mathematics · 04/03/2021

  5. max acceleration a = Aω² ω² = a/A = 10m/s² / 0.741m = 13.5 rad/s² and also ω² = k/m, so 13.5 rad/s² = k / 5.8kg making k = 78.3 kg/s² (or N/m) total energy TME = ½kA² = ½ * 78.3N/m * (0...

    2 Answers · Science & Mathematics · 04/03/2021

  6. ...3 *(Pi*√3) = 4*Pi = 0.2  Pi = 0.2/4 = 0.05 = 1/20 or 5 cm /s <<< Ps = Pi *√3 = 0...

    1 Answers · Science & Mathematics · 03/03/2021

  7. radius = 0.25 cm = 0.0025 m area = πr² = 0.00001964 m² R = (1.68e-8)(5000)/(0...

    1 Answers · Science & Mathematics · 03/03/2021

  8. You must be consistent with units.  Either use dm for everything which gives a result in Litres and kg or work in m^3 which gives a result in tonnes.  Volume displaced is 4*6 * 0.04 = 0.96 m^3 and with a mass of 1 tonne / m^3 this is...

    1 Answers · Science & Mathematics · 02/03/2021

  9. max acceleration a = Aω² = A(2πf)² = 4π²Af² so a = 10 * 9.81m/s² = 4π² * 0.095m * f² solves to f = 5.11 s⁻¹ = 5.11 Hz

    1 Answers · Science & Mathematics · 03/03/2021

  10. a) PE becomes KE: ½kx² = ½mv² ½ * 600N/m * (0.0617m)² = ½ * 1.69kg * V² solves to V = 1.16 m/s b) PE becomes KE and friction work: ...

    1 Answers · Science & Mathematics · 02/03/2021

  1. Try asking your question on Yahoo Answers