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  1. The horizontal force (due to the field) is Fx = q*E = q*V/d = q * 7.99e-3V / 0.155m = q*0.05155V/m The geometry of the string gives the geometry of the forces: tanΘ = Fx / m*g Fx = q*0.05155V/m = 0.00640kg * 9.81m...

    1 Answers · Science & Mathematics · 07/01/2021

  2. spring constant k = F/x = 300/0.3 = 1000 N/m spring energy SE = k/2*x'^2 = 1000/2*0.85^2 = 361 joule Energy at the bottom of the incline  BIE : BIE = SE-m*g*μ *d = 361-10*9.8*6*0.13 = 285 joule distance L up the incline BIE = m*g*L*(sin 30°+cos 30°*μi) 285...

    3 Answers · Science & Mathematics · 14/01/2021

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