### A block of mass 2.5 kg is attached to a horizontal spring that has a force constant of 1.40 103 N/m?

Given: m = 2.5 kg k = 1.40e3 N/m xi = -5.5

**cm**= -0.055 m (a) work W = ½k(xi)² = ½...1 Answers · Science & Mathematics · 21/10/2020

...55 m3/yr is the first step to m^3/year 1 m^3 is 100x100x100

**cm**^3 = 1,000,000**cm**^3 1 year approximates as 365.25 days or 8,765...3 Answers · Science & Mathematics · 20/10/2020

500.0 rev/min / 60 s/min = 8.33 rev/s Let's find the angular acceleration θ = θ₀ + ω₀t + ½αt² 210.0 = 0 + 8.33(35.0) + ½α35.0² α = -0.133 rev/s² A. At what rate is the flywheel spinning when the power...

1 Answers · Science & Mathematics · 20/10/2020

it is formed into two squares? basically, if z is one piece and y is the other z + y = x sides of each are z/4 and y/4 areas are z²/16 and y²/16 sum is z²/16 + y²/16 12(z/4) = y/4 12z = y x = z + y = z + 12z = 13z...

1 Answers · Science & Mathematics · 20/10/2020

... / (πd²/4) = 4*1100

**cm**³/s / π(0.50**cm**)² = 5602**cm**/s = 560 m/s v = 4*1100**cm**³/s / π(2.0**cm**)² = 350**cm**/s = 35 m/s...1 Answers · Science & Mathematics · 20/10/2020

net force = weight - electrostatic force m*a = m*g - qV/d q = m*(g - a)*d / V q = 1.50e-14kg * (9.81 - 1.80)m/s² * 0.0940m / 980V q = 1.15e-17 C (an excess of 72 electrons) Not much of a diagram; just the weight down (m*g) and the electrostatic force up (q*E = q*V/d; the field...

3 Answers · Science & Mathematics · 19/10/2020

find the velocity of the block + bullet mass just after impact a = 2s/t² = 2(0.80)/2.0² = 0.4 m/s² v = at = 0.4(2) = 0.8 m/s conservation of momentum during the impact 0.025u + 25.0(0) = (25.0 + 0.025)(0.8) u = 800.8 ≈ 801 m/s Please remember to select a Best Answer from among your...

2 Answers · Science & Mathematics · 19/10/2020

Hey, were these workings helpful? https://answers.yahoo.com/question/index?qid=20201019033203AAqwDSh https://answers.yahoo.com/question/index?qid=20201019033122AAMGW3g

1 Answers · Science & Mathematics · 20/10/2020

...e) PS = PE 1.5 = 1.0(9.8)h h = 0.15306... ≈ 15.3

**cm**f) 1.5 J Spring potential has converted to gravity...1 Answers · Science & Mathematics · 18/10/2020

...283k = 1.01e5Pa * d³ / 293K solves to d = 0.89

**cm**Hope this helps!1 Answers · Science & Mathematics · 19/10/2020