...just indicating the image is real} =>di = [8 x 4.5]/6 =>di = 6

**cm**b) By m = hi/ho = 4.5/6 = 0.75 c) For concave mirror, this condition...1 Answers · Science & Mathematics · 06/11/2020

We know the pen is the hypotenuse of a triangle with base² = 12²+12² = 288 17² = 288+h² h² = 17²-288 = (1

**cm**)² so the box has height 1**cm**assuming the pen width can be ignored.1 Answers · Science & Mathematics · 11/11/2020

Nodal line = minima for second Nodal line total path difference = 3λ/2 (29.5 -25) = 3λ/2 λ = 3

**cm**a) wavelength = 3**cm**b) f = v/λ = 7.5/3 = 2.5 Hz Please Rate me Kohul !!1 Answers · Science & Mathematics · 31/10/2020

... at first nodal point 1er n =1 ∴ ∆ Sn = 1/2 x 2.5

**cm**∆ Sn =1.25m Please Rate me Kohul !!1 Answers · Science & Mathematics · 31/10/2020

y ≈ nλD/d y ≈ 3 * 450e-9m * 1.3m / 6e-6m ≈ 0.29 m or 29

**cm**1 Answers · Science & Mathematics · 31/10/2020

Treating 90

**cm**as "distant" y ≈ (n+½)λD / d 0.21 m ≈ (2+½)*λ*0.90m / 6e-6m λ ≈ 5.6e-7 m = 560 nm1 Answers · Science & Mathematics · 31/10/2020

@amy's hints are sound. vertically, T*sinΘ = m*g T = 0.185kg * 9.81m/s² / sin13.0º = 8.07 N horizontally, T*cosΘ = mω²r = mω²LcosΘ ω² = T / mL = 8.07N / (0.185kg * 0.680m) = 64.1...

2 Answers · Science & Mathematics · 30/10/2020

minimum speed such that g = v²/r v = √(gr) = √(9.81m/s² * 0.580m) = 2.39 m/s time to fall from h = (2.45 + 0.58)m = 3.03 m t = √(2h / g) = √(2 * 3.03m / 9.81m/s²) = 0.786 s distance to right x = v*t = 1.87 m If you find this helpful, please select Favorite Answer!

1 Answers · Science & Mathematics · 30/10/2020

field E = potential / distance = 200V / 0.20m = 1000 V/m 1. a = F/m = qE/m = 1.6e-19C * 1000N/C / 1.67e-27kg a = 9.58e10 m/s² 2. d = ½at² t = √(2d/a) = √(2*0.20m / 9.58e10m/s²) = 2.04e-6 s or ≈ 2 µs 3. I = q / t...

1 Answers · Science & Mathematics · 25/10/2020

...so the distance between pith balls is d = 2*15

**cm***sin14º = 7.26**cm**The geometry of the string gives the geometry of the forces...1 Answers · Science & Mathematics · 21/10/2020