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1. Physics Grade 10 Need urgent help  ?

...just indicating the image is real} =>di = [8 x 4.5]/6 =>di = 6 cm b)  By m = hi/ho = 4.5/6 = 0.75 c) For concave mirror, this condition...

1 Answers · Science & Mathematics · 06/11/2020

2. Math Problem Help?

We know the pen is the hypotenuse of a triangle with base² = 12²+12² = 288 17² = 288+h² h² = 17²-288 = (1cm)² so the box has height 1cm assuming the pen width can be ignored.

1 Answers · Science & Mathematics · 11/11/2020

3. 2 point sources vibrate in phase at the same frequency. They set up an interference pattern in which a point on the 2nd nodal line is 29.5cm?

Nodal line = minima for second Nodal line  total path difference = 3λ/2 (29.5 -25) = 3λ/2 λ = 3 cm a) wavelength = 3 cm b) f = v/λ = 7.5/3 = 2.5 Hz Please Rate me Kohul !!

1 Answers · Science & Mathematics · 31/10/2020

4. Two point sources S1 and S2 vibrate in phase and produce waves of length 2.5m. The 2 waves overlap at a nodal point. Calculate the smallest?

... at first nodal point 1er n =1 ∴ ∆ Sn = 1/2 x 2.5 cm    ∆ Sn =1.25m Please Rate me Kohul !!

1 Answers · Science & Mathematics · 31/10/2020

5. A monochromatic light source of wavelength 450nm illuminates 2 slits that are 6 x 10^-6 m apart. Find the distance to the 3rd order maximum?

y ≈ nλD/d y ≈ 3 * 450e-9m * 1.3m / 6e-6m ≈ 0.29 m or 29 cm

1 Answers · Science & Mathematics · 31/10/2020

6. Find the wavelength of light used if the 2nd order minimum is located 21cm from the central maximum on a screen 90cm away. The separation?

Treating 90 cm as "distant" y ≈ (n+½)λD / d 0.21 m ≈ (2+½)*λ*0.90m / 6e-6m λ ≈ 5.6e-7 m = 560 nm

1 Answers · Science & Mathematics · 31/10/2020

7. If I swing a ball from a 68.0 cm string in a horizontal circle over my head. Suppose the ball has a mass of 185 g, and during their motion ?

@amy's hints are sound. vertically, T*sinΘ = m*g T = 0.185kg * 9.81m/s² / sin13.0º = 8.07 N horizontally, T*cosΘ = mω²r = mω²LcosΘ ω² = T / mL = 8.07N / (0.185kg * 0.680m) = 64.1...

2 Answers · Science & Mathematics · 30/10/2020

8. In the figure, a 120 g ball on a 58.0 cm rope is swung in a vertical circle about a point 245 cm  ?

minimum speed such that g = v²/r v = √(gr) = √(9.81m/s² * 0.580m) = 2.39 m/s time to fall from h = (2.45 + 0.58)m = 3.03 m t = √(2h / g) = √(2 * 3.03m / 9.81m/s²) = 0.786 s distance to right x = v*t = 1.87 m If you find this helpful, please select Favorite Answer!

1 Answers · Science & Mathematics · 30/10/2020

9. Physics question ?

field E = potential / distance = 200V / 0.20m = 1000 V/m 1. a = F/m = qE/m = 1.6e-19C * 1000N/C / 1.67e-27kg a = 9.58e10 m/s² 2. d = ½at² t = √(2d/a) = √(2*0.20m / 9.58e10m/s²) = 2.04e-6 s or ≈ 2 µs 3. I = q / t...

1 Answers · Science & Mathematics · 25/10/2020

10. Physics problem - electrostatic unit?

...so the distance between pith balls is d = 2*15cm*sin14º = 7.26 cm The geometry of the string gives the geometry of the forces...

1 Answers · Science & Mathematics · 21/10/2020