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...which has a positive solution we can ignore and a negative solution at x = -58.9 cm c) Now the field is zero somewhere between the charges. ...

Again LMAO at your answer to Pearl! :D yay ok...ok  um  *chews junk*  (what do you want, i'm a cat!) You'd chew YOUR junk if you colud!  (Remember you tried, and hurt your back, and you told your mother it...

...velocity v(t) = ds/dt = 5π*cos(πt) - 5π*sin(πt) At t = 1, v(1) = -5π cm /s ≈ -15.71 cm /s a) Find s(t) for each time, subtract the difference, and divide...

The initial kinetic energy after impact is converted to friction work ½mv² = μmgd       v = √(2μgd) = √(2(0.4)(9.8)(0.15)) = 1.0844... m/s conservation of momentum during the collision  0.400(u) + 14(0) = 14.4(1.0844) u = 39.0396... ≈ 39 m/s◄ Please remember to select a...

That is no doubt admitting the government is dishonest and void of impartial descision under law. More important than how that reflects on her we must accept what she is telling us; our government is corrupt. 

kinetic energy theorem: 1/2 m v^2 = 1/2 k (xo^2 - x^2) - m g (x - x0) |v| = |2 k (xo^2 - x^2) / m - g (x - x0)|^1/2 |v| = |(xo - x) [2 k (x + xo) / m - g]|^1/2 |v| = |(0.142 - 0.05)*[ 2*23.4*(0.142 + 0.05) / 1.1 - 9.8]|^1/2 = 0.39 m/s moving away from equilibrium if it was on horizontal surface without friction: 1/2 m v^2 = 1/2 k (xo^2 - x^2) v = [k (xo^2...

work = spring energy = ½kx² W = ½ * 78.1N/m * (0.511m)² = 10.2 J If you find this helpful, please select Favorite Answer!

magnitude if Spring force, F = kx ma = kx a = kx/m a = (52 N/m)(0.043 m)/(0.075 kg) a ≈ 30 m/s²