Yahoo Web Search

  1. Sort by

  1. 21.3 cm / 1.3 cm = 16.38461538 cm. Since the least number of significant figures is 2, the answer would be: 16 cm.

    1 Answers · Science & Mathematics · 28/09/2010

  2. 1/λ = 1953 cm^-1 ∴ λ = 1/1953 = 5.12×10^-4 cm = 5.12×10^-6 m = 5.12 μm (10^-6 m) = 5120...

    1 Answers · Science & Mathematics · 05/10/2014

  3. CM's approach is valid.. i like to "scale up" from STP - idk...

    2 Answers · Science & Mathematics · 26/11/2010

  4. 3.291 g/cm^3 or g/mL With significant digits (if you are supposed to use it) 3 g/mL or 3g/cm^3

    4 Answers · Science & Mathematics · 03/10/2011

  5. Okay, well the fact that the volume is expressed in cm^3 doesn't matter in terms of putting it into the equation, just in...

    1 Answers · Science & Mathematics · 10/06/2010

  6. (30.5 cm x 3048 cm) / (13.5 cm x 9.5 cm) x (0.69 g) / (26.98154 g Al/mol) x (6.022 x 10^23 atoms/mol) = 1.12 x 10^25 atoms Al ($5.49) / (1.12 x 10^25 atoms) = $4.90 x 10^-25 / atom Al

    1 Answers · Science & Mathematics · 06/05/2013

  7. 3.00 cm × 3.00 cm × 0.725 dm = 0.03 m × 0.03 m × 0.0725 m = 6.525×10^-5 m^3; m = density*volume = 1.738×103 kg/m3 * 6.525×10^-5 m^3 = 0.113 kg.

    1 Answers · Science & Mathematics · 19/09/2013

  8. ...careful about units i.e. you can't multiply volume in cm^3 and density in kg/m^3 and expect a good answer, you 1st... (1000 cm^3) or water. Density of sugar = 1.6 g/cm^3, water is 1 g/cm^3 So mass of sugar is...

    1 Answers · Science & Mathematics · 10/07/2017

  9. First, Calculate the volume of the gold ingot. 2.00 cm × 4.00 cm × 7.00 cm = 56cm3 Second, using density formular of D...

    1 Answers · Science & Mathematics · 30/09/2013

  10. 5.00 mL = 5.00 cm^3 X (1 m/100 cm)^3 = 5.00X10^-6 m^3 Volume = ...

    1 Answers · Science & Mathematics · 09/11/2016

  1. Try asking your question on Yahoo Answers