1 mole = 22.4 liters 22.4 liters × .005 = .112 liters = 112 cm³ ³√112 = 4.82

**cm**edge length.1 Answers · Science & Mathematics · 28/05/2020

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2 Answers · Science & Mathematics · 29/05/2020

dh/dt = 3 dA/dt = 4.5 h = 11 A = 97 A = (1/2) * b * h 97 = (1/2) * b * 11 194/11 = b A = (1/2) * b * h dA/dt = (1/2) * (b * dh/dt + h * db/dt) 4.5 = (1/2) * ((194/11) * 3 + 11 * db/dt) 9 = 582/11 + 11 * db/dt 9 - 582/11 = 11 * db/dt (99 - 582) / 11 = 11 * db/dt -483/121 = db/dt

1 Answers · Science & Mathematics · 26/05/2020

...m=torr is 30 torr over normal atmospheric pressure. You would need over 40

**cm**of water column on the outside of the collection vessel to keep the collected gas...1 Answers · Science & Mathematics · 26/05/2020

Exact question: https://answers.yahoo.com/question/index?qid=20200522022256AA4g9c5

3 Answers · Science & Mathematics · 22/05/2020

...wire can't possibly be this much. You have 3.08 * 10^-4 m^3. 8.8 g/

**cm**^3 = 8800 kg/m^3 = 2.71 kg For the second question, I'll...3 Answers · Science & Mathematics · 21/05/2020

A=l*w 56= 2l + 2w; w= 28 - l A= l*(28 - l)= 28l - l² dA/dl= 28 - 2l= 0 l= 14

**cm**, w= 14**cm**4 Answers · Science & Mathematics · 19/05/2020

...10 = e-1 (rarely used) c (cent) = /100 = e-2 (rarely used except for

**cm**) m (milli) = /1000 = e-3 µ (micro) = /1000000 = e-6 n (nano) = /1000000000 = e-9 p...5 Answers · Science & Mathematics · 17/05/2020

The force = 0 where E = 0. Like charges oppose between but add outside so look between where the opposing E fields are equal. Factor out k and 1e-9 -6/x² = -3/(0.6-x)² +6/x² = +3/(0.6-x)² +6(0.6-x)²...

1 Answers · Science & Mathematics · 13/05/2020

...2.00*d² This quadratic has a root at d = 0.245 m = 24.5

**cm**◄ our solution and d = 1.09 m ← outside the permitted range ...1 Answers · Science & Mathematics · 13/05/2020