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  1. Cosec and sec are the reciprocals of SIN and COS. Arc cos(X) is the angle whose cosine is X Arc sin(X) is the angle whose sin is X

    5 Answers · Science & Mathematics · 13/02/2009

  2. In Trinidad, CSEC results will be released to schools either on Thursday...

    5 Answers · Science & Mathematics · 25/08/2008

  3. dx+ csec^2(xy).( xdy + ydx)=0 dy(x csec^2(xy)=(-1-ycsec^2(xy))dx dy/dx=(-1-ycsec^2(xy))/(x csec^2(xy)

    4 Answers · Science & Mathematics · 28/10/2012

  4. cscx / (cotx + tanx ) = csec x /( 1/tan x + tan x) = csc x / ((1+ tan ^2 x)/tan x) = csc x tan x / (sec ^2 x) = (1/sin x) (sin x/cos x) cos ^2 x = cos ^2 x/ cos x = cos x proved by math kp

    2 Answers · Science & Mathematics · 02/06/2008

  5. math SBA? are you doing CAPE or CSEC mathematics? if so, then the SBA component for CAPE is 3 module tests (i think) CSEC Math doesnt have any SBAs

    1 Answers · Science & Mathematics · 29/10/2007

  6. Yes Observe sin(x) cos(x) tan(x) cot(x) sec(x) csec(x) 1/sin(x)=csec(x) 1/cos(x)=sec(x) 1/tan(x) =cot(x) also sin(x)/cos(x)=tan...

    4 Answers · Science & Mathematics · 24/01/2007

  7. No. a TI-Basic program doesn't have any where near the capability of doing what you want. You would have to program it in Z80 Assembly, which is by far too tedious. If you have a cable that connects the TI-84 Plus to...

    1 Answers · Science & Mathematics · 25/01/2010

  8. ...2(x)]/cos(x)(x) - Dsin(x)[tan^2(x)] = Acos(x) - Bsin(x) + Csec(x) - Ccos(x) - Dsin(x)*[sec^2(x) - 1] = Acos(x) - Bsin...

    1 Answers · Science & Mathematics · 05/05/2012

  9. left part tan x = sinx / cosx cot x = cosx / sinx sin²x + cos²x = 1 ((sinx)² + (cosx)²) / (cosx*sinx) = 1 / (cosx* sinx) right part sec = 1 / cosx csec = 1 / sinx 1 / (sinx*cosx) so left = right

    4 Answers · Science & Mathematics · 09/01/2010

  10. becuase csc^2 x -c cot^2 x = 1 multiply both num and den by csc x - cot x = tan x(csec x - cot x) = tan x csc x - 1 = sinx / cos x * 1/ sin x -1 = sec x -1 so ans is a

    2 Answers · Science & Mathematics · 24/03/2007

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