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1. ### âˆ« (cscâˆšx) dx / âˆšx ...........?

âˆ« (cscâˆšx)/âˆšx dx put u = âˆšx, then du = 1/(2âˆšx) dx ==> 2 du = 1/âˆšx dx. ... you remember the anti-derivative of the cosecant as a formula---it is -ln|csc(u) + cot(u)|. If not, there is a way to arrive at this. Multiply...

1 Answers Â· Science & Mathematics Â· 19/11/2010

2. ### csc arcos? Trigonometry help?

csc(arccos(2 / sqrt(13)) Remember that: sin(t)^2 + cos(t)^2 = 1 and sin(t) = 1 / csc(t) So: (1/csc(t))^2 + cos(t)^2 = 1 (1/csc(arccos(2/sqrt(13...

1 Answers Â· Science & Mathematics Â· 26/02/2012

3. ### find csc@ + cot@ = 1?

cscÎ¸ +cotÎ¸ = 1 1/sinÎ¸ + cosÎ¸/sinÎ¸ = 1 1 + cosÎ¸ = sinÎ¸ sinÎ¸ - cosÎ¸ = 1 ...cosÎ¸ = 0 Î¸ = {Ï€/2, 3Ï€/2, 5Ï€/2....} Check: If sinÎ¸=0, cscÎ¸ and cotÎ¸ are undefined. If Î¸=Ï€/2 cscÎ¸ = 1 cotÎ¸ =0 cscÎ¸+cot...

1 Answers Â· Science & Mathematics Â· 06/05/2008

4. ### how to integrate csc^6X?

âˆ« csc^6x dx = change the sign: - âˆ« (- csc^6x) dx = rewrite the integrand as: - âˆ« (csc^4x) (- csc^2x) dx = rewrite (csc^4x) in terms of cotx: - âˆ« (csc^2x)^2 (- csc...

3 Answers Â· Science & Mathematics Â· 26/12/2008

5. ### Integral of cot^2(x)csc(x) dx?

âˆ« cotÂ²x csc x dx = rewrite cotÂ²x as (cscÂ²x - 1): âˆ« (cscÂ²x - 1) csc... csc x - csc x) dx = and break it up into: âˆ« cscÂ²x csc x dx - âˆ« csc x dx = as for the first integral, let: cscÂ²x dx = dv â†’ - cot x = v...

3 Answers Â· Science & Mathematics Â· 29/06/2008

6. ### Evaluate the following integral: (csc^(3)x) dx ?

âˆ«csc^3(x) dx integrate by parts let u = csc x : du = - csc x cot x dv = csc^2(x) dx : v = - cot x...dx = - csc x cot x + âˆ« csc x dx => 2 âˆ«csc^3(x) dx = - csc x cot x - ln I csc x + cot x I + c âˆ«csc...

2 Answers Â· Science & Mathematics Â· 01/01/2010

7. ### Prove : (cscÎ¸/cscÎ¸-1) + (cscÎ¸/cscÎ¸+1) = 2secÂ²Î¸?

[csc Î¸ / (csc Î¸ - 1)] + [csc Î¸ / (csc Î¸ + 1)] = 2 secÂ²Î¸ ~~~~~~~~~~~~~~~~~~~~~~~~~ METHOD... the LCD. (csc Î¸ - 1) * (csc Î¸ + 1) = (csc Î¸ - 1)(csc Î¸ + 1) Multiply each fraction on the LHS as ...

4 Answers Â· Science & Mathematics Â· 04/11/2008

8. ### derivative of f(x) = âˆš( ( tan( csc(âˆšx) ) ) / ( sinÂ³x * cot(2x) ) )?

f = âˆš[tan(cscâˆšx)/(sin^3(x) cot(2x))] df/dx = 1/2 * 1/âˆš[tan(cscâˆšx)/(sin^3x cot2x)] * d[tan(cscâˆšx)/(sin^3x cot2x)]/dx d[tan(cscâˆšx)/(sin...3sin^2x * cosx * cot2x - 2csc^2(x) * sin^3x d(cscâˆšx)/dx = -1/(2âˆšx) * cot(âˆšx)csc(âˆšx) d...

1 Answers Â· Science & Mathematics Â· 15/12/2013

9. ### pre calc/ trigonometry-- solve: cot/(csc + 1)?

cot x / (csc x + 1). Multiply by (csc x - 1) / (csc x -1). Basically that is the same as multiplying by 1. [cot x /(csc x+1)] x [(csc x -1)(csc x -1)] = [(cot x csc x - cot x) / cot^2 x] Then...

3 Answers Â· Science & Mathematics Â· 21/02/2008

10. ### What is 1/x^2 (csc(2/x)+ sec(2/x))^2 dx using integration?

Take the integral: âˆ« (csc(2/x) + sec(2/x))Â²/xÂ² dx Expanding the integrand (csc(2/x...(2/x))/xÂ² dx + âˆ« (secÂ²(2/x))/xÂ² dx +2 âˆ« (csc(2/x) sec(2/x))/xÂ² dx For the integrand (csc(2/x) sec(2/x))/...

3 Answers Â· Science & Mathematics Â· 24/12/2012

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