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1. ### ∫ (csc√x) dx / √x ...........?

∫ (csc√x)/√x dx put u = √x, then du = 1/(2√x) dx ==> 2 du = 1/√x dx. ... you remember the anti-derivative of the cosecant as a formula---it is -ln|csc(u) + cot(u)|. If not, there is a way to arrive at this. Multiply...

1 Answers · Science & Mathematics · 19/11/2010

2. ### csc arcos? Trigonometry help?

csc(arccos(2 / sqrt(13)) Remember that: sin(t)^2 + cos(t)^2 = 1 and sin(t) = 1 / csc(t) So: (1/csc(t))^2 + cos(t)^2 = 1 (1/csc(arccos(2/sqrt(13...

1 Answers · Science & Mathematics · 26/02/2012

3. ### Calc Help! ∫csc^4 2x dx Integration!?

csc^4 2x dx Let u= 2x du = 2 dx dx = (1/2) du ∫ csc^4 2x dx = (1/2) ∫ csc^4 u du = (1/2) ∫ csc^2 u csc...1/2) ∫ t^2 dt = (-1/2)(1/3) t^3 = (-1/6) cot^3 u ∫ csc^4 2x dx = (-1/2) cot u - (1/6) cot^3 u replace u by 2x...

1 Answers · Science & Mathematics · 15/08/2014

4. ### find csc@ + cot@ = 1?

cscθ +cotθ = 1 1/sinθ + cosθ/sinθ = 1 1 + cosθ = sinθ sinθ - cosθ = 1 ...cosθ = 0 θ = {π/2, 3π/2, 5π/2....} Check: If sinθ=0, cscθ and cotθ are undefined. If θ=π/2 cscθ = 1 cotθ =0 cscθ+cot...

1 Answers · Science & Mathematics · 06/05/2008

5. ### how to integrate csc^6X?

csc^6x dx = change the sign: - ∫ (- csc^6x) dx = rewrite the integrand as: - ∫ (csc^4x) (- csc^2x) dx = rewrite (csc^4x) in terms of cotx: - ∫ (csc^2x)^2 (- csc...

3 Answers · Science & Mathematics · 26/12/2008

6. ### Integral of cot^2(x)csc(x) dx?

∫ cot²x csc x dx = rewrite cot²x as (csc²x - 1): ∫ (csc²x - 1) csc... csc x - csc x) dx = and break it up into: ∫ csc²x csc x dx - ∫ csc x dx = as for the first integral, let: csc²x dx = dv → - cot x = v...

3 Answers · Science & Mathematics · 29/06/2008

7. ### Evaluate the following integral: (csc^(3)x) dx ?

csc^3(x) dx integrate by parts let u = csc x : du = - csc x cot x dv = csc^2(x) dx : v = - cot x...dx = - csc x cot x + ∫ csc x dx => 2 ∫csc^3(x) dx = - csc x cot x - ln I csc x + cot x I + c ∫csc...

2 Answers · Science & Mathematics · 01/01/2010

8. ### Prove : (cscθ/cscθ-1) + (cscθ/cscθ+1) = 2sec²θ?

[csc θ / (csc θ - 1)] + [csc θ / (csc θ + 1)] = 2 sec²θ ~~~~~~~~~~~~~~~~~~~~~~~~~ METHOD... the LCD. (csc θ - 1) * (csc θ + 1) = (csc θ - 1)(csc θ + 1) Multiply each fraction on the LHS as ...

4 Answers · Science & Mathematics · 04/11/2008

9. ### derivative of f(x) = √( ( tan( csc(√x) ) ) / ( sin³x * cot(2x) ) )?

f = √[tan(csc√x)/(sin^3(x) cot(2x))] df/dx = 1/2 * 1/√[tan(csc√x)/(sin^3x cot2x)] * d[tan(csc√x)/(sin^3x cot2x)]/dx d[tan(csc√x)/(sin...3sin^2x * cosx * cot2x - 2csc^2(x) * sin^3x d(csc√x)/dx = -1/(2√x) * cot(√x)csc(√x) d...

1 Answers · Science & Mathematics · 15/12/2013

10. ### pre calc/ trigonometry-- solve: cot/(csc + 1)?

cot x / (csc x + 1). Multiply by (csc x - 1) / (csc x -1). Basically that is the same as multiplying by 1. [cot x /(csc x+1)] x [(csc x -1)(csc x -1)] = [(cot x csc x - cot x) / cot^2 x] Then...

3 Answers · Science & Mathematics · 21/02/2008