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  1. ... gave the relationship between Volume and Pressure:  "V of air varies inversely with the pressure P" which means that...

    3 Answers · Science & Mathematics · 11/07/2013

  2. ... both sides w.r.t time P dV/dt + V dP/dt=0 You have V=600 cm^3 P=100 kPa...

    2 Answers · Science & Mathematics · 14/07/2013

  3. Use p.V = constant (pressure times volume) Boyle's law 4 * 7.5 = 6.5 * V V = 4.62

    1 Answers · Science & Mathematics · 02/05/2013

  4. PV = c w.r.t. time. So dc/dt = 0. P*dV/dt + V*dP/dt = 0 dP/dt = (-P/V)*(dV/dt) = (-450 kPa) / (250 cm^3) * (15 cm^3 / min) = -27 kPa / min

    2 Answers · Science & Mathematics · 27/04/2013

  5. ...10,000 x 4 = 40,000 = constant i.e. PV = 40,000 => P = 40,000/V => dP/dV = -40,000/V² Now, dV/dt = 8 and...

    2 Answers · Science & Mathematics · 24/04/2013

  6. Differentiating w.r.t t we get PdV/dt+VdP/dt=0 Substitute values & find the unknown value

    1 Answers · Science & Mathematics · 24/04/2013

  7. k = P * V k = 14.7 lb/in^2 * 71.2 ft^3 = 1046.64 lb-ft^3 / in^2 V = P / k V = 2250 lb/in^2 / 1046.64 lb-ft^3/in^2 V = 2.15 ft^3

    1 Answers · Science & Mathematics · 10/04/2013

  8. ... 150 ml. This is known as Boyle's Law. It's written as PV = P'V' where P and V are the original...

    1 Answers · Science & Mathematics · 09/02/2013

  9. ... site? However let us have a go :- P = k/V k = PV k = 20.6 x 50.25 k = 1035.15 P = 1035.15 / V V...

    1 Answers · Science & Mathematics · 23/02/2014

  10. Let p = pressure, v = volume, and t = time. p = k/v for some k. 1 = k/200 k = 200 p = 200/v d/dt(p...dp/dt = -200(dv/dt)/v^2 Substitute 10 * 0.1 = 1 for dp/dt and 200 for v, and solve for dv/dt. 1 = -200(dv/dt)/200^2 1 = -dvdt/200 dv/dt = -200 cm^3/min

    1 Answers · Science & Mathematics · 25/12/2012

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