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... variables: dt = dm/(am^(3/4) -

**bm**) Integrate both sides: t = ∫ dm/(am...^(1/4)) ==> bt/4 = ln [(a - bm₀^(1/4))/(a -**bm**^(1/4))] Take exponentials of both ...1 Answers · Science & Mathematics · 10/08/2013

**bm**+ 7r + rm + 7b**bm**+ rm + 7b + 7r (**bm**+ rm) + (7b + 7r) m(b + r) + 7(b + r) (m + 7)(b + r)3 Answers · Science & Mathematics · 06/12/2006

...sin(alpha) = a/c and cos(alpha) =b/c. The median

**BM**is the hypotenuse of a right triangle and ...sqrt [3(sin(alpha) )^2 +(sin(alpha))^2+ ( cos(alpha) )^2]**BM**= c/2 sqrt [3(sin(alpha) )^2 +1] tan(MBC...1 Answers · Science & Mathematics · 19/08/2013

i) Median AN &

**BM**intersect at K; so K is the centroid of the triangle ABC...1 Answers · Science & Mathematics · 21/06/2016

ax-

**bm**+an-bn just take the common terms ax + an -**bm**- bn= a(x+n) - b(m+n)4 Answers · Science & Mathematics · 09/05/2009

I'll assume Am is between A and B,

**Bm**is between B and C, and Cm is between C and...7 Answers · Science & Mathematics · 04/11/2007

...and B, and that AM=4x-10. If that's true, then AM =

**BM**(picture a line with M exactly between points A and B...1 Answers · Science & Mathematics · 22/10/2009

AB = AM +

**BM**AB = 4x - 2 + 5x - 10 AB = 9x - 12 AM =**BM**4x - 2 = 5x - 10 4x - 5x = -10 + 2 -x = -8 x = 8 substitute x = 8 into AB; AB = 9(8) - 12 AB = 72 - 12 AB = 606 Answers · Science & Mathematics · 27/01/2009

abx^2 + (an +

**bm**)x + mn abx^2 + anx + bmx + mn factor by grouping ax(bx + n) + m(bx + n) (ax + m)(bx + n) -9x^2 + 6(y + 5)x - 5(2y + 5) 3x[-3x + 2(y + 5)] - 5(2y + 5) 3x(-3x + 2y + 10) - 5(2y + 5)2 Answers · Science & Mathematics · 11/09/2011

AB^2+AC^2=4+4a^2+4b^2, M is (a+1,b) so

**BM**^2+AM^2=(a-1)^2+b^2+(a+1)^2+b^2=2+2a^2+2b^2 so 2(**BM**^2+...1 Answers · Science & Mathematics · 17/02/2012