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  1. Ag+ + Br- --> AgBr 0.1L x 2x10^-6M = 2x10^-7moles Ag+ 0.1L x 2x10^-3M = 2x10^-4moles Br- these bind in a 1:1 ratio Ag+ is the limiting reactant and will only bind with 2x10^-7moles of Br...

    1 Answers · Science & Mathematics · 10/11/2011

  2. test today for warren? first of all, for the Ag+= equation, you used mmols from your...plug back in to Ag+= .02404/(2.9e13*3.6597e-6) [Ag+] = 2.26e-10 ***Now that I look at it...

    1 Answers · Science & Mathematics · 16/04/2013

  3. ...be obtained by multiplying the concentration of Ag+ and Cl- at anytime; if the product of the ...this is vague since i don't know the concentration of Ag+ in the 2 mL solution

    2 Answers · Science & Mathematics · 23/06/2012

  4. ... sur mer 62200 - FRANCE) 1 / 5.3g of Ag ? - - - - - - - - - - - Avogadro's number... 1 mole of AgCl contains 1 mole of Ag . . . then : n(Ag) = n(AgCl) = 2,60•10...

    1 Answers · Science & Mathematics · 15/12/2011

  5. First, balance the equation. Ag(s) + 2 HNO3(aq) --> NO2(g) + H2O...element and charge on both sides.) and now you have: Ag(s) + 2H+(aq) +2NO3-(aq) --> NO2(g...

    3 Answers · Science & Mathematics · 11/06/2008

  6. ... is added to make it soluble and this results in the form, Ag(NH3)2(+). When it reacts with the hydrate of an aldehyde, it...

    1 Answers · Science & Mathematics · 27/09/2012

  7. ... is correct in discussing Ag+ as a Lewis acid, but not correct on AgCl...left, in favor of the dissolved ferric ion. Ag+ is not sufficiently electron-deficient to do that...

    3 Answers · Science & Mathematics · 24/05/2012

  8. AgI = Ag^+ + I^- Ksp = [Ag^+]*[I^-] Here Ksp = 8...

    1 Answers · Science & Mathematics · 02/03/2014

  9. Reactant oxidation nos: n(Cl) = -1 n(Ag+) = +1 In the product compound n(Ag) = +1 n(Cl) = -1 the oxidation...

    1 Answers · Science & Mathematics · 17/04/2013

  10. ... a filled d-sublevel and one valence electron in the 5s-sublevel. Ag+ ion has lost the 5s-electron. Two ammonia molecules can combine...

    1 Answers · Science & Mathematics · 27/01/2015

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