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... 3x3 is more complex: a b c d e f g h i would have a determinant:

**aei**+ bfg + cdh - gec - hfa - idb2 Answers · Science & Mathematics · 26/09/2009

...i | Downhill Diagonals - Uphill Diagonals =

**aei**+ bfg + cdh - ceg - fha - ibd GOOD LUCK2 Answers · Science & Mathematics · 04/12/2007

...i | Downhill Diagonals - Uphill Diagonals =

**aei**+ bfg + cdh - ceg - fha - ibd GOOD LUCK3 Answers · Science & Mathematics · 04/12/2007

...e ... f ] ... d ... e ... f [ g ... h ... i ] ... g ... h ... i Determinant = (

**aei**+ bfg + cdh) - (ceg + bdi + afh)2 Answers · Science & Mathematics · 16/04/2012

...point to the same circle are equal] v) Now consider triangles

**AEI**& AFI, EI = FI [From 3 above] AE = AF...3 Answers · Science & Mathematics · 28/02/2013

... to check). ========== Note, determinant of a b c d e f g h i =

**aei**+ bfg + cdh - gec - hfa - idb x = det( 11 7 4 4 1 -1 15 -6 1)/ det( 3 7 4 1...1 Answers · Science & Mathematics · 10/02/2009

...last 6 dinner parties should have the following guests: [7]

**AEI**[8] AFH [9] BDI [10] BFG [11] CDH [12] CEG...1 Answers · Science & Mathematics · 10/05/2009

...d e f d e g h i g h 2. then multiply the main diagonals and add

**aei**+ bfg + cdh 3. multiply the opposite diagonals and add gec + hfa + idb 4...2 Answers · Science & Mathematics · 11/12/2007

..., ABI, ABJ ACD, ACE ADE AEG,

**AEI**, AEJ AIJ BCF, BCI BDJ BEH, ...2 Answers · Science & Mathematics · 12/12/2009

adjustments need to be made for the fact that there are some letters occurring more than once. the permutation formula for such cases is n! /(r1!*r2!*.....) where there are r1 letters of one kind, r2 of another kind, etc A2 R1...

3 Answers · Science & Mathematics · 12/07/2011

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