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  1. ... 3x3 is more complex: a b c d e f g h i would have a determinant: aei + bfg + cdh - gec - hfa - idb

    2 Answers · Science & Mathematics · 26/09/2009

  2. ...i | Downhill Diagonals - Uphill Diagonals = aei + bfg + cdh - ceg - fha - ibd GOOD LUCK

    2 Answers · Science & Mathematics · 04/12/2007

  3. ...i | Downhill Diagonals - Uphill Diagonals = aei + bfg + cdh - ceg - fha - ibd GOOD LUCK

    3 Answers · Science & Mathematics · 04/12/2007

  4. ...e ... f ] ... d ... e ... f [ g ... h ... i ] ... g ... h ... i Determinant = (aei + bfg + cdh) - (ceg + bdi + afh)

    2 Answers · Science & Mathematics · 16/04/2012

  5. ...point to the same circle are equal] v) Now consider triangles AEI & AFI, EI = FI [From 3 above] AE = AF...

    3 Answers · Science & Mathematics · 28/02/2013

  6. ... to check). ========== Note, determinant of a b c d e f g h i = aei + bfg + cdh - gec - hfa - idb x = det( 11 7 4 4 1 -1 15 -6 1)/ det( 3 7 4 1...

    1 Answers · Science & Mathematics · 10/02/2009

  7. ...last 6 dinner parties should have the following guests: [7] AEI [8] AFH [9] BDI [10] BFG [11] CDH [12] CEG...

    1 Answers · Science & Mathematics · 10/05/2009

  8. ...d e f d e g h i g h 2. then multiply the main diagonals and add aei + bfg + cdh 3. multiply the opposite diagonals and add gec + hfa + idb 4...

    2 Answers · Science & Mathematics · 11/12/2007

  9. ..., ABI, ABJ ACD, ACE ADE AEG, AEI, AEJ AIJ BCF, BCI BDJ BEH, ...

    2 Answers · Science & Mathematics · 12/12/2009

  10. adjustments need to be made for the fact that there are some letters occurring more than once. the permutation formula for such cases is n! /(r1!*r2!*.....) where there are r1 letters of one kind, r2 of another kind, etc A2 R1...

    3 Answers · Science & Mathematics · 12/07/2011

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