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...cosθ = (1 + k)(1 - CD^2) / [2√(k(1 - CD^2))] ---(#5) Think △

**ACE**. By the sine law , CE / sin(∠CAE) = AC / sin(∠AEC...1 Answers · Science & Mathematics · 04/04/2017

...in time or space. If I draw two cards from a deck and get two

**aces**, that is a coincidence, whether the deal is rigged or not. If...2 Answers · Science & Mathematics · 07/04/2017

...'s the math: there are 4 royal flushes that are 10-

**Ace**. so that is 4 instances. To figure out the number...3 Answers · Science & Mathematics · 27/02/2017

You add how many

**aces**there are total (4) and how many clubs there are total (13). There are 17 cards that you could choose, out of a possible 52. so 17/52 chance2 Answers · Science & Mathematics · 27/02/2017

... two cards. What the probability that the 2nd is an

**Ace**. (it's 4/525). That the second has probability of 2/17 of...2 Answers · Science & Mathematics · 17/01/2017

...same for b) and c) For c) you might have to make assumptions about

**aces**(are they high or low?) d) There are no cards between...1 Answers · Science & Mathematics · 02/01/2017

... 52 cards in the deck. 1. The probability of drawing a red

**ace**is 2/52. The probability of then drawing an**ace**of any ...2 Answers · Science & Mathematics · 02/01/2017

The ratio of men to women is 4 to 1. Usually the first step is to add up the numbers in the ratio: 4+1 = 5. Now you can rephrase it as 4 of every 5 workers is a man. That's 80%. 80% of 300 is 240. The...

4 Answers · Science & Mathematics · 17/12/2016

Probability distribution of X (number of

**aces**) X --------------------- P(X) 0 --- 4C0*48C5 / 52C5...1 Answers · Science & Mathematics · 18/12/2016

There are 2 red

**aces**P( red**ace**) = 2/52 = 1/26 P( black**ace**) = 1/26 Yes. These two values are the same. P( red**ace**, black**ace**) + P( black**ace**, red**ace**) = (2/52)(2/51) + (2/52)(2/51) = 2/6632 Answers · Science & Mathematics · 12/12/2016

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