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P(at least 1

**Ace**) = 1 - P(both no**aces**) P(1st card no**ace**) = number...51 P(both no**aces**) = 48/52 * 47/51 = 2256/2652 P(at least 1**Ace**) = 1 - P(both no**aces**) = 1 - (2256/2652) = 396/26522 Answers · Science & Mathematics · 20/01/2018

It's important FIRST to practice the stuff you already know how to do, so that you feel 100% confident about it, and hardly ever make a mistake. This is MORE important than trying to get a vague idea of how to do "everything else." When you have a sense of real mastery in at least a...

5 Answers · Science & Mathematics · 09/01/2018

...sure of my answer) There are 52x30 = 1560 cards and 30

**ace**of spades n=10 (number of cards drawn) 10 ...2 Answers · Science & Mathematics · 08/06/2019

... = 1 (radius of the circle) CE = CB - EB = 5 - 1 = 4 ∠

**ACE**= 90° (property of the tangency) AC² = CE² - EA² AC²...2 Answers · Science & Mathematics · 21/12/2017

If you draw 3 cards from each suit, the probability that they include four

**aces**is (3/10)^4 = 81/10000. There are various ways to approach...2 Answers · Science & Mathematics · 25/12/2017

The probability of getting the first

**ace**on the nth draw is p(n) = (1/13)(12/13)^(n-1). That's the probability...2 Answers · Science & Mathematics · 05/12/2017

...11 PROBLEM 1b. There are 2 ways to draw a black

**ace**(**Ace**of spades and**Ace**of clubs) There ...1 Answers · Science & Mathematics · 22/11/2017

7 out of 13 52 cards, 26 are red +2 black

**aces**makes the -probability of 28 out of 52 that you will get an**ace**or a red card 28/52 reduces to 7/13 or 53.8462%2 Answers · Science & Mathematics · 07/11/2017

The word "pair" almost always means 2. And it often means two objects that are meant to go together, or that are matched in some way. A pair of gloves. A pair of

**aces**.4 Answers · Science & Mathematics · 07/09/2017

26/52 * 4/52 There are 26 black cards in a deck of 52 and 4

**aces**.4 Answers · Science & Mathematics · 04/07/2017

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