##### Ads

related to**ACE**

Sort by

- Relevance
- |Time

13 clubs plus 3

**aces**from the other suits plus 3 face cards per suit times three other suits = 253 Answers · Science & Mathematics · 05/10/2007

... you do your way, you're saying I have to get an

**ace**, then a two etc so there are less possible ways. When you ...1 Answers · Science & Mathematics · 12/06/2013

There's 13 hearts. There's 3

**aces**that aren't hearts. So, there's 16 favorable cards, in a set of 52 cards. The chance of drawing them are 16/52 = 4/131 Answers · Science & Mathematics · 07/04/2014

... of two queens: C(4, 2) = 6 Combinations of one black

**ace**: C(2, 1) = 2 Combinations of 4 cards drawn form...1 Answers · Science & Mathematics · 10/11/2016

... the 4 Queens, pick 2. 4C2 = 6 ways From the 4

**Aces**, pick 1. 4C1 = 4 ways 6 × 6 × 4 = 144 Answer: C...2 Answers · Science & Mathematics · 04/01/2017

Not including Jokers. 52 cards in the deck,4 face cards, 4

**aces**. 4+4=8. 8 out of 52 8 out of 52 is your answer1 Answers · Science & Mathematics · 09/07/2013

There is no substitute for practice. Try every question you can get your hands on, and then try a few more for good measure. :)

4 Answers · Science & Mathematics · 09/06/2012

He can get: 4

**aces**+ (1 or 0) faces 3**aces**+ (2, 1, 0) faces 2**aces**...or a big pain to do all by hand. Here are the payoffs:**aces**0 faces 0: -2.50**aces**0 faces 1: -1.00**aces**0...1 Answers · Science & Mathematics · 09/11/2010

I'd say 1,000?

3 Answers · Science & Mathematics · 24/01/2012

P(

**ace**)=2/6=1/3 n=6 p=1/3 P(one**ace**) = (2/6)(4/5) = 8/30 P(2**aces**) = (2/6)(1/5) = 2/30 P( at least one**ace**) = 8/30+2/10 = 10/30=1/3 P(**ace**,**ace**) = (2/6)(1/5) = 2/30 = 1/153 Answers · Science & Mathematics · 08/01/2010

##### Ads

related to**ACE**