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... we threw away all the other cards and just had 4

**aces**and 12 face cards. We can do this because if we draw any other card we...1 Answers · Science & Mathematics · 18/02/2017

...to consider cases. There are 2 cases to consider: 1)

**Ace**of spades is drawn, 2)**ace**of spades isn't ...1 Answers · Science & Mathematics · 19/10/2013

...a bunch of times. Each time you deal, you record the number of

**aces**, and the number of spades on a sheet of paper (like make three ...1 Answers · Science & Mathematics · 23/06/2013

...8 = 10 and the 1 + 3 = 4 Now, to YOUR problem. Choose 1

**ace**from 4 cards, and 4 "others" from 48 cards = 4 ...2 Answers · Science & Mathematics · 25/03/2014

i will instead break it up into i = non-club

**aces**, 1 to 3, and j =**ace**of clubs, 0 to 1, k = non-**ace**clubs, 0 to 12...1 Answers · Science & Mathematics · 31/03/2013

it is taken that # of spades is also exactly 5

**aces**: 3 non-spade, 1 spade kings: 3 non-spade, 1 spade other spades: 11...2 Answers · Science & Mathematics · 27/09/2010

...39;m assuming this is a standard deck of 52 cards and 4

**aces**, and that the cards are drawn then replaced one at a...2 Answers · Science & Mathematics · 07/04/2009

...4 C 2) first: number of ways of choosing 3

**aces**second: number of ways of choosing the rank for the...1 Answers · Science & Mathematics · 21/03/2010

... X the number of different ways to select 2 out of 4

**Aces**X the number of different ways to select 1 more card from the...1 Answers · Science & Mathematics · 24/09/2014

4C3*12C1*4C2 = 4*12*6 = 288 Pick three

**aces**(out of four) = 4C3 Pick one rank between 2 and King (twelve) = 12C1 Pick one pair (2) from the four of than rank = 4C21 Answers · Science & Mathematics · 21/03/2010

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