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**aces**can be selected from 4 in 4C3 ways and balance one card from... => there are 48C3 x 48 ways of getting 3**aces**out of 52C4 total n umber of getting any 4 cards. => ...4 Answers · Science & Mathematics · 11/01/2010

Start with the

**aces**. There are 4 possibilities for the 1st**ace**. ...difference which order you actually draw the**aces**in.**Ace**of spades and**ace**of hearts is the same as**ace**of hearts and**ace**of ...1 Answers · Science & Mathematics · 04/05/2013

There are FOUR

**Aces**. You MUST choose 3 of the 4. You... did that totally wrong, it should be 2**aces**and 3 non-**aces**...doesn't really change much here...4 Answers · Science & Mathematics · 01/06/2010

...hypergeometric distribution to find the solution Let X be the number of

**aces**drawn. X has the hypergeometric distribution with the following...4 Answers · Science & Mathematics · 22/03/2008

1. 4

**aces**and 26 - 2 (**aces**) red cards...so 28 out of 52 28/52= 7/13 answer...5 Answers · Science & Mathematics · 19/02/2007

Ok so 2

**aces**and a king are removed so that leaves 52 - 3 = 49 cards...(first card is an**ace**) = 2/49 As we do not replave the**ace**, there are now 48 cards in the deck and there is only 1**ace**...1 Answers · Science & Mathematics · 26/05/2015

...trouble getting an answer here because people don't know what you mean by an

**ace**. It may be, in this kind of activity, that a true probability can't be ...1 Answers · Science & Mathematics · 15/03/2008

...’s add things up assuming that the

**Ace**comes before the King. Then the...this nature. The probability is 1/52 that the**Ace**is in position 1 (I'll just write A...2 Answers · Science & Mathematics · 04/11/2015

... are 4 x 48 = 192 combinations of 2-card hands with 1

**ace**. There are 52C2 = 26x51 = 1326 ways to deal those two...2 Answers · Science & Mathematics · 19/03/2014

**Ace**high only or 1**ace**in your hand? What level of math are you working with. To simply get an**ace**is 1 in 13, however if you are really looking for**ace**high then...2 Answers · Science & Mathematics · 20/05/2008

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