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  1. ..., then there are 12 of them. There are 4 aces and 36 others. There are 4C2 ways of ...

    6 Answers · Science & Mathematics · 13/11/2007

  2. ... to choose from. Otherwise, we have a 4-card hand with at most two aces and no kings. Then no aces → 44C4 possible ...

    1 Answers · Science & Mathematics · 27/06/2010

  3. ... = 1287X4=5148 hands 2) There are 4 aces and 48 not-aces. You want 3 choices from 4 = 4 with 2...

    1 Answers · Science & Mathematics · 05/11/2013

  4. ...version, which contains the first version as a special case), how many aces are there? How many aces do you want to choose? How many...

    1 Answers · Science & Mathematics · 25/01/2011

  5. a) Any 5 cards...so 52!/5!/47! = 2,598,960 b) no aces...so 48!/5!/43! = 1,712,304

    1 Answers · Science & Mathematics · 22/06/2013

  6. ...,Q). There's 44 because 52 minus 4 kings and 4 aces = 44. So in our final stage of the prob tree there would be a total of...

    1 Answers · Science & Mathematics · 06/06/2010

  7. ... a seven is 1/13 The probability of picking an ace is the same....1/13 So the probability of both occurring is...

    4 Answers · Science & Mathematics · 09/06/2015

  8. ... using combinations there is 1 red joker and 2 red aces either one or 2 cards have to come from these 3 so reqd.probability = (3C1...

    1 Answers · Science & Mathematics · 23/09/2009

  9. ... is that you have 52 cards and classify them as 4 each of Ace through Nine, that's 36 16 cards worth 10, that's 16 ...

    4 Answers · Science & Mathematics · 19/02/2016

  10. Quit asking questions, and do it kid! If you want to ace it, hit the books! Just get a good nights rest before, and have a kick ass breakfast on test day!

    2 Answers · Science & Mathematics · 15/04/2011

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