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  1. qa 12 ranks remain for forming pair excluding 3 aces Pr = 4c3*12c1*4c2 = 4*12*6 = 288 <---- qb (choose rank) *(choose...

    3 Answers · Science & Mathematics · 16/05/2013

  2. ... 3 random cards and having one of them be an ace and the other two being kings = (4 choose 1)(4 choose 2)/(52 choose 3...

    2 Answers · Science & Mathematics · 14/05/2013

  3. to win, your opponent must have one of the following: straight (53) trips two pair pocket pair bigger than 7 split pair (A or J) 7 with a bigger kicker than 8 we count the number of hands of each type, sum, and divide by 45C2, the total...

    2 Answers · Science & Mathematics · 05/07/2013

  4. Okay, so we've got an ace turned up and four cards turned down... in the 4 down cards could include the other three aces. Each of these must be a combination of the aces...

    1 Answers · Science & Mathematics · 27/06/2013

  5. Perfect! It's nice to someone that understands the difference between odds and probability.

    1 Answers · Science & Mathematics · 14/07/2013

  6. The center point of the circle is labled C. The diameter, or central chord, a straight line through the center (C) connects with the outside of the circle at points A and B. So there is a line through the center of te circle with three...

    2 Answers · Science & Mathematics · 19/04/2013

  7. 1. at least 3 means 3 or 4 or 5: 6c3*18c2 + 6c4*18c1 +6c5 = 3336 <------- 2. similarly, 4c2*20c2 + 4c3*20c1 +4c4 = 1221 <--------

    1 Answers · Science & Mathematics · 29/04/2013

  8. ... many ways can you deal a 2 card blackjack hand which includes the Ace of Spades? 1) A of spades + one of 51 other cards...

    1 Answers · Science & Mathematics · 22/04/2013

  9. population mean (claim) = 1150000/2500 = 460 population standard deviation = 210 a) P(x < 357) = P(z < (357-460)/210) = P(z < -.49) = .3120669483 <---answer b) population mean = 1000000/2500 = 400 sample mean = 8975/25 = 359 standard error = 210/sqrt(25...

    1 Answers · Science & Mathematics · 30/03/2013

  10. i will instead break it up into i = non-club aces, 1 to 3, and j = ace of clubs, 0 to 1, k = non-ace clubs, 0 to 12...

    1 Answers · Science & Mathematics · 31/03/2013

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