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... of cards in the deck = 52 Total number of

**Aces**= 4 Total number of non-**Aces**= 52 - 4 = 48 Number of...1 Answers · Science & Mathematics · 15/10/2009

... purposes there are only 3 types of cards:

**Aces**(A), tens or picture cards (T) and numbers less...2 Answers · Science & Mathematics · 19/02/2016

...52*51*50*49*48) = 60 / (52*51*50*49) = 1 / (26*17*5*49) = 1/108290 b) P(3

**aces**exactly) = (4C3) * (48C2) / (52C5) = 4 * (48*47/2) / (52*51*50*49...5 Answers · Science & Mathematics · 22/06/2011

...2) * (4 choose 3)) / (52 choose 5) = 9.23446302 × 10^(-6) 2 # ways to get 3

**aces**= 4 choose 3 # ways to get 2 other cards from all 48 non-**aces**...3 Answers · Science & Mathematics · 14/06/2011

... P(red) = 26/52 = 0.5. In a 52-card deck, there are 4

**aces**, so the probability of choosing an**ace**is P(**ace**) = 4/52 = 0.0769...2 Answers · Science & Mathematics · 28/07/2015

Five cards consists of 1 King (0/1/2)

**Ace**and (4/3/2) other cards Required probability = (4C1*4C0...2 Answers · Science & Mathematics · 23/06/2010

... (260 cards) into 52 5-card hands. There will be 20

**aces**in 52 hands, for 20/52 = 0.385, which is the same as 4**aces**...1 Answers · Science & Mathematics · 26/02/2011

...question. Mr. A has 5 cards, exactly 1 is an

**Ace**, so the remainder of the deck is 47 cards, with 3**Aces**...1 Answers · Science & Mathematics · 20/10/2010

...48! * 39! * 4 * 40 ----------------------- = p(1) 36! * 52! p(picking exactly 2

**aces**) = 48/52 * 47/51 * ...* 38/42 * 4/41 * 3/40 * 40nCr2 48! * 39! * 40 * 39 * 4...1 Answers · Science & Mathematics · 20/09/2008

...3456/9139 ≈ 37.8% PART D: Pick the suits for the two

**aces**: C(4,2) = 4 x 3 / (2 x 1) = 6 ways Pick the suits...2 Answers · Science & Mathematics · 04/10/2014

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