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  1. Angle BCD = 85 (60+25 - exterior angle) And, Angle ACE = 85 (vertically opposite to BCD) Therefore, Angle CAE = 55 (Angle sum Triangle = 180 - (180-85-40 = 55))

    1 Answers · Science & Mathematics · 12/06/2016

  2. ...get a four-of-a-kind, you have to have the flop be the last 3 cards of either aces or jacks. So the first card can be any of the 6 remaining...

    2 Answers · Science & Mathematics · 16/02/2016

  3. ... purposes there are only 3 types of cards: Aces (A), tens or picture cards (T) and numbers less...

    2 Answers · Science & Mathematics · 19/02/2016

  4. ... is that you have 52 cards and classify them as 4 each of Ace through Nine, that's 36 16 cards worth 10, that's 16 ...

    4 Answers · Science & Mathematics · 19/02/2016

  5. ...single card of a third rank?" There are 13 ranks (Ace, 2 through 10, Jack, Queen, and King). So there ...

    1 Answers · Science & Mathematics · 09/01/2016

  6. ... P(red) = 26/52 = 0.5. In a 52-card deck, there are 4 aces, so the probability of choosing an ace is P(ace) = 4/52 = 0.0769...

    2 Answers · Science & Mathematics · 28/07/2015

  7. ... a seven is 1/13 The probability of picking an ace is the same....1/13 So the probability of both occurring is...

    4 Answers · Science & Mathematics · 09/06/2015

  8. a/ There are 10 sequences of ranks for forming a straight flush, and 4 suits, thus # of ways = 10c1 *4c1 = 40 <----- b/ Choose rank for pair and choose pair x choose 3 other ranks, and a card each from them # of...

    1 Answers · Science & Mathematics · 01/11/2014

  9. ...3456/9139 ≈ 37.8% PART D: Pick the suits for the two aces: C(4,2) = 4 x 3 / (2 x 1) = 6 ways Pick the suits...

    2 Answers · Science & Mathematics · 04/10/2014

  10. ... X the number of different ways to select 2 out of 4 Aces X the number of different ways to select 1 more card from the...

    1 Answers · Science & Mathematics · 24/09/2014

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