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  1. 13 clubs plus 3 aces from the other suits plus 3 face cards per suit times three other suits = 25

    3 Answers · Science & Mathematics · 05/10/2007

  2. ... you do your way, you're saying I have to get an ace, then a two etc so there are less possible ways. When you ...

    1 Answers · Science & Mathematics · 12/06/2013

  3. There's 13 hearts. There's 3 aces that aren't hearts. So, there's 16 favorable cards, in a set of 52 cards. The chance of drawing them are 16/52 = 4/13

    1 Answers · Science & Mathematics · 07/04/2014

  4. ... of two queens: C(4, 2) = 6 Combinations of one black ace: C(2, 1) = 2 Combinations of 4 cards drawn form...

    1 Answers · Science & Mathematics · 10/11/2016

  5. ... the 4 Queens, pick 2. 4C2 = 6 ways From the 4 Aces, pick 1. 4C1 = 4 ways 6 × 6 × 4 = 144 Answer: C...

    2 Answers · Science & Mathematics · 04/01/2017

  6. Not including Jokers. 52 cards in the deck,4 face cards, 4 aces. 4+4=8. 8 out of 52 8 out of 52 is your answer

    1 Answers · Science & Mathematics · 09/07/2013

  7. There is no substitute for practice. Try every question you can get your hands on, and then try a few more for good measure. :)

    4 Answers · Science & Mathematics · 09/06/2012

  8. He can get: 4 aces + (1 or 0) faces 3 aces + (2, 1, 0) faces 2 aces...or a big pain to do all by hand. Here are the payoffs: aces 0 faces 0: -2.50 aces 0 faces 1: -1.00 aces 0...

    1 Answers · Science & Mathematics · 09/11/2010

  9. P(ace)=2/6=1/3 n=6 p=1/3 P(one ace) = (2/6)(4/5) = 8/30 P(2 aces) = (2/6)(1/5) = 2/30 P( at least one ace) = 8/30+2/10 = 10/30=1/3 P( ace,ace) = (2/6)(1/5) = 2/30 = 1/15

    3 Answers · Science & Mathematics · 08/01/2010

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