... is 60 degrees and the triangle is equilateral, therefore angle

**ABP**must be 60 degrees. By definition, the angle ABC must be 135...3 Answers · Science & Mathematics · 04/05/2010

Area of triangle = 0.5 (base)(height) base = AB = 2 height = P to center of AB = FB Using Pythagoras's Theorem, height = √ [(2^2) + (2^2)] height = √8 height = 2√2 Area of triangle = 0.5 (2) (2√2) Area of triangle = 2√2...

1 Answers · Science & Mathematics · 13/10/2008

CP x DP = AP x BP 16 x 4 = 8 x BP BP=8

1 Answers · Science & Mathematics · 07/06/2009

Draw the circle with centre O and from point P draw tangents PA and PB as described in your question. note that length OA = length OB = radius R of the circle given lengthOP = diameter D = 2...

3 Answers · Science & Mathematics · 22/02/2010

45 degrees

1 Answers · Science & Mathematics · 16/04/2013

... is cyclic → triangles

**ABP**and CDP are equiareal. The center... its area. (2) Triangles**ABP**and CDP are equiareal → ABCD...2 Answers · Science & Mathematics · 10/01/2010

(i) The triangle

**ABP**will, in general, not have any side parallel to either of the ...1). One triangle that is part of this but not in**ABP**has corners at A, (p, p^2 - 2), (2...1 Answers · Science & Mathematics · 20/08/2011

every cicle could be drawn by means of center and radius, so here we should find the radius, Center(-1,3) and tangent to the line y=22, means that the radius is 22-3=19 so (x+1)^2+(y-3)^2=19^2 Center(4,-2) and tangent to the line x=1, means that the radius is 4-1=3 so (x...

1 Answers · Science & Mathematics · 06/11/2009

**ABP**forms a triangle & <**ABP**=180*-47*20'-78*10'=> <**ABP**=54.5*=> <**ABP**=54*30' By the sine rule, ...1 Answers · Science & Mathematics · 02/12/2012

Let <

**ABP**=a,then <PBC=a too. Now suppose there is another...2 Answers · Science & Mathematics · 21/09/2008