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  1. ... is 60 degrees and the triangle is equilateral, therefore angle ABP must be 60 degrees. By definition, the angle ABC must be 135...

    3 Answers · Science & Mathematics · 04/05/2010

  2. Area of triangle = 0.5 (base)(height) base = AB = 2 height = P to center of AB = FB Using Pythagoras's Theorem, height = √ [(2^2) + (2^2)] height = √8 height = 2√2 Area of triangle = 0.5 (2) (2√2) Area of triangle = 2√2...

    1 Answers · Science & Mathematics · 13/10/2008

  3. Draw the circle with centre O and from point P draw tangents PA and PB as described in your question. note that length OA = length OB = radius R of the circle given lengthOP = diameter D = 2...

    3 Answers · Science & Mathematics · 22/02/2010

  4. ... is cyclic → triangles ABP and CDP are equiareal. The center... its area. (2) Triangles ABP and CDP are equiareal → ABCD...

    2 Answers · Science & Mathematics · 10/01/2010

  5. (i) The triangle ABP will, in general, not have any side parallel to either of the ...1). One triangle that is part of this but not in ABP has corners at A, (p, p^2 - 2), (2...

    1 Answers · Science & Mathematics · 20/08/2011

  6. every cicle could be drawn by means of center and radius, so here we should find the radius, Center(-1,3) and tangent to the line y=22, means that the radius is 22-3=19 so (x+1)^2+(y-3)^2=19^2 Center(4,-2) and tangent to the line x=1, means that the radius is 4-1=3 so (x...

    1 Answers · Science & Mathematics · 06/11/2009

  7. ABP forms a triangle & <ABP=180*-47*20'-78*10'=> <ABP=54.5*=> <ABP=54*30' By the sine rule, ...

    1 Answers · Science & Mathematics · 02/12/2012

  8. Let <ABP=a,then <PBC=a too. Now suppose there is another...

    2 Answers · Science & Mathematics · 21/09/2008

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