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Aabb X aaBb Steps:- 1.First, write gametes of both...-3 Fill those boxes. --------Ab--------ab---- aB--- AaBb ---- aaBb -- ab--- Aabb ----- aabb --

AaBB - gives gametes AB and aB aaBb - gives...and ab Offspring are AaBB , AaBb , aaBB and aaBb . aaBB = 1 in 4. Aa x aa - gives 1 in 2 chance of aa...

AABB - 1 in 16. Aabb - 1 in 8. Treat each separately -eg. Aa x Aa gives 1n 4 AA. Bb x Bb gives 1 in 4 BB. So, AABB = 1/4 x 1/4 = 1/16.

AABB X aabb gives AaBb . AaBb x AaBb gives... with a phenotypic ratio of 9:3:3:1. Only one will have the genotype AABB . See link for results. Answer = a.

AaBB x AABb parent 1 gametes AB, aB parent 2 gametes AB Ab F1 AABB , AABb , AaBB , AaBb The term monhybrid and dihybrid refer to the number of loci you...

AaBb X AaBb a) AABb = 1/4 X 1/2 = 1/8 AaBB ...

AABb gives the gametes AB & Ab. ---------AB----------Ab AB..... AABB ..... AABb Ab...... AABb ..... AAbb 3 genotypes. 2 phenotypes.

AaBb gives 4 gametes = AB, Ab, aB and ab aaBb ... = aB and ab A 4 x 2 Punnett square gives - AaBB , AaBb , aaBB , aaBb , AaBb , Aabb , aaBb , aabb ...