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Yes it is possible. If the computer that the

**N**.**J**. IP is assigned to has no (or sloppy) security it could...3 Answers · Computers & Internet · 21/07/2011

...

**j**=i*2; while(**j**<=**n**) { if((**j**<**n**)&&(**a**[**j**]<**a**[**j**+1]))**j**++; if(**a**[**j**]<...1 Answers · Computers & Internet · 19/08/2010

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**j**=i*2; while(**j**<=**n**) { if((**j**<**n**)&&(**a**[**j**]<**a**[**j**+1]))**j**++; if(**a**[**j**]<...1 Answers · Computers & Internet · 14/08/2010

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**j**=i*2; while(**j**<=**n**) { if((**j**<**n**)&&(**a**[**j**]<**a**[**j**+1]))**j**++; if(**a**[**j**]<...2 Answers · Computers & Internet · 14/08/2010

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**j**=i*2; while(**j**<=**n**) { if((**j**<**n**)&&(**a**[**j**]<**a**[**j**+1]))**j**++; if(**a**[**j**]<...1 Answers · Computers & Internet · 14/08/2010

...complexity b) for (i = 0; i <

**n**; i +=**a**) for (**j**= 0;**j**<**n**;**j**+=**a**) S; Since**a**is very small with reference to**n**, we can assume...3 Answers · Computers & Internet · 23/04/2013

B) o

**J**= 0**a**= 1 c = 2 k = 3 (space) = 4**J**= 5 o = 6 ...1 Answers · Computers & Internet · 22/12/2010

exactly, it should be

**N**^2 because when you increment**N**, your cycle will execute**N**^2 times.2 Answers · Computers & Internet · 08/05/2012

...int v=

**a**[i]; int**j**=i*2; while(**j**<=**n**) { if((**j**<**n**)&&(**a**[**j**]<**a**[**j**+1]))**j**++; if(**a**[**j**]<**a**[**j**/2]) break;**a**[**j**/2...1 Answers · Computers & Internet · 22/08/2010

...for (int i=0; i<

**n**; ++i) { for (int**j**=0;**j**<**n**; ++**j**) {**a**[i][**j**] = 100*i +**j**+ 101; } } for (int i=0; i<**n**; ++i...2 Answers · Computers & Internet · 02/10/2018

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