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  1. Delta E = -2.18X10^-18 (1/ n ^2f - 1/ n ^2i) Delta E = -2.18X10^-18 (1/4 - 1/49) = -5.00X10^-19 J /photon E = hc/wavelength 5.00X10^-19 J = 6.626X10^-34...

    1 Answers · Science & Mathematics · 30/09/2020

  2. ...(s) …. E° = 0.34 V Gas constant, R = 8.314 J /(mol K) Temperature, T = 298 K Number of electrons involved, n = 2 1 F = 96485 F Nernst equation: Reduction potential...

    2 Answers · Science & Mathematics · 01/04/2020

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