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  1. .../m² J = Nxm so.. Pa x N x m^4 / J = ( N /m²) x ( N ) x m^4 / J = N² x m² / J ...

    2 Answers · Science & Mathematics · 23/02/2011

  2. Thomas Alva Edison was one of the greatest inventors of all time. Sounds like you found an antique bottle of battery oil. His companies didn't fare well. Much of his effort to form companies...

    2 Answers · Science & Mathematics · 12/10/2006

  3. In Denver. This is because at higher elevations there is less pressure in the atmosphere, so the water boils at a lower temperature.

    5 Answers · Science & Mathematics · 02/12/2006

  4. We can find the energy (E) from the wavelength (w) by: E = hc/w where h is Planck's constant, 6.625 * 10**-34 joule-sec. and c the speed of light which is 3.0 * 10**8 meters per sec. so E = hc/w We can find w from the lower (L) and upper (U...

    1 Answers · Science & Mathematics · 02/02/2013

  5. is this one element or is it a list of elements? need more clarification :)

    2 Answers · Science & Mathematics · 02/08/2011

  6. ...would use is E=Rh [(1/ni^2)-(1/nf^2)] Rh is a constant (for hydrogen) and is 2.18 x 10^-18 J ni- is n initial nf is n final so 2.18 x 10^-18 J (1/2^2) -(1/3^2) 2...

    1 Answers · Science & Mathematics · 13/07/2009

  7. ...where l is the wavelenght corresponding to a particle of mass m moving at the speed v. h = ...x 10E-27 ergs.sec = 6.62 x 10E-34 J .sec One of the 1st evidences of this...

    1 Answers · Science & Mathematics · 09/11/2009

  8. ...from one level ( n initial) to another level ( n final). The -2.178x10^-18J... to remove the electron from a hydrogen atom in its ground...s measured in Joules ( J ) and is a constant in the equation...

    1 Answers · Science & Mathematics · 30/11/2017

  9. ... energy in joules h is Planck's constant (6.626e-34 Js ) c is speed of light (2.998e+8 ms^-1) Step one: we know what...

    1 Answers · Science & Mathematics · 02/04/2009

  10. d.3.16 10^5 J the energy af a single photon is E = hv and v = c / λ so E = hc / λ E = 6... = photon enrgy*avogadro's number = 5.25*10^-19 * 6.02*10^23 = 3.16*10^5 J = 316 kJ

    1 Answers · Science & Mathematics · 21/06/2008

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