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... way to answer this question is probably to look in your text book for

**a**table of the functional groups and their peak ranges. ...1 Answers · Science & Mathematics · 20/10/2008

E= Ek +W = hf W = hf - 3.50× 10^-19 J = 1,7*10^-18 J f ' = 2,56*10^15 3.19× 10^–7 J = h*f' * n = h*2,56*10^15* n n = 1,876*10^11 photons / e-

1 Answers · Science & Mathematics · 13/10/2013

... - V1 ) V1 = nRT1/P

**n**= 1.15 X 10^2 / molar mass of NO2 = 1.15 ... -7.44 = 29.76 L atm now 1 L atm = 101.3**J**so W = 29.76 X 101.3 = 3014.688**J**hope...1 Answers · Science & Mathematics · 12/03/2014

... you re in organic one, so you don t need to know this but here:

**a**) OH b) carbonyl, C=O (any, but if anhydride you ll...carbonyl R-CH3 I) I don t know, maybe nitrile,**N**=-C (triple bond)2 Answers · Science & Mathematics · 02/04/2011

...4356975

**N**/ m2) (-3.0 *10-3 m3) = 13070**N**m = 13070**J**= 13.07 kJ We know that at consatnt pressure q...2 Answers · Science & Mathematics · 25/10/2008

...the molar heat of reaction. q = mcΔT = 100g H2O x 4.18

**J**/gC x 5C = 2090**J**moles of NaOH = 2.02 g ...1 Answers · Science & Mathematics · 29/11/2012

...constant of HOCl from 5 to 35 °. J . Phys. Chem. 70:3798-3805... andproperties n , ?r, etc. Thermodynamicdata... acid is a weak acid with the chemical formula ...

3 Answers · Science & Mathematics · 25/01/2007

...that into the equation E=RH[(1/ni^2)-(1/nf^2)] where u would guess at the

**n**values however u know that in order for absorption to occur**n**must increase in value...1 Answers · Science & Mathematics · 26/10/2013

...

**J**/atom) x [(6.022x10^23 atoms)/(1 mole)] = -1.18x10^7**J**/mol or -1.18x10^4 kJ/mol. If we assume that... is minimal between two electrons in**a**1s orbital then the total amount of energy required for...2 Answers · Science & Mathematics · 21/09/2010

... just p times final V. Of course, who knows what

**a**torr is...Google says it's 133.3 Pascals. Note that 1 Pa = 1**N**/m^2, so 1 Pa times 1 m^3 is 1 Newton-meter = 1...1 Answers · Science & Mathematics · 29/01/2012

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