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  1. ...standard representation is " bold v " = (a_1) j_1 + (a_2) j_2 + ... + (a_n) j_n where j_i are unit vectors in independent directions ...

    1 Answers · Science & Mathematics · 29/01/2013

  2. n(j(x)) = 5/((-6 + 20/(-2 + x)) (-2 + x)) = 5/(32 - 6 x)

    1 Answers · Science & Mathematics · 30/07/2015

  3. ...of 1I_J ) P( X € A ) = Integral ( x € A n J) dx finally, if you have understood all this (this is what i hope...

    1 Answers · Science & Mathematics · 02/03/2014

  4. ...from N. Then, if i > j, then n(i) > n(j), and so a(n(i)) >= a(n(j)). Thus, a(n(m)) is monotone increasing. Decreasing...

    1 Answers · Science & Mathematics · 04/02/2012

  5. ...i) = 1 * (2^(n - j + 1) - 1) / (2 - 1) = 2^(n - j + 1) - 1 Therefore: a_n = ∑ (j = 1 to n) ∑ (i = j to n) 2^(n - i) = ∑ (j = 1 to n) [2^(n - j + 1) - 1] = ∑ (j...

    1 Answers · Science & Mathematics · 30/06/2013

  6.   (x + 1/x)^6 = Σ [k=0 to 6] C(6,k) x^(6−k) (1/x)^k To find term with x^3, then find k so that exponent of x is 3 in x^(6−k) (1/x)^6 x^(6−k) (1/x)^k = x^3 x^(6−k) / x^k = x^3 x^(6−k−k) = x^3 6−2k = 3 No integer value of k gives us an exponent of 3. So (x + 1/x)^6...

    1 Answers · Science & Mathematics · 09/05/2017

  7. ...identity matrix: its value 0. It is created by the sum of A(n,j)*B(j,n-1) = 0 As all elements of the last row of A...

    1 Answers · Science & Mathematics · 07/04/2014

  8. If A, B and N are given, why don't you give them to me so I can work with them!?!?!? I = (N-K+A)/N J = (N-L+B)/N

    1 Answers · Science & Mathematics · 05/09/2012

  9. ...matrix. That is, for any j: a(1, j)b(1, j) + a(2, j)b(2, j) + ... + a(n, j)b(n, j) = 0 But then, all the action happens in the jth column, where...

    1 Answers · Science & Mathematics · 11/03/2014

  10. ... the n-th root of the product of all n of them: GM(a[1], ..., a[n]) = (∏[j=1,n] a[j])^(1/n) For n = 2, this is GM(a, b) = √(ab...

    3 Answers · Science & Mathematics · 15/04/2011

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