# Yahoo Web Search

1. Sort by

1. ### help: algebra question?

If A, B and N are given, why don't you give them to me so I can work with them!?!?!? I = (N-K+A)/N J = (N-L+B)/N

1 Answers · Science & Mathematics · 05/09/2012

2. ### Combinatorics Question (Tower of Hanoi, recursion)?

...i) = 1 * (2^(n - j + 1) - 1) / (2 - 1) = 2^(n - j + 1) - 1 Therefore: a_n = ∑ (j = 1 to n) ∑ (i = j to n) 2^(n - i) = ∑ (j = 1 to n) [2^(n - j + 1) - 1] = ∑ (j...

1 Answers · Science & Mathematics · 30/06/2013

...from N. Then, if i > j, then n(i) > n(j), and so a(n(i)) >= a(n(j)). Thus, a(n(m)) is monotone increasing. Decreasing...

1 Answers · Science & Mathematics · 04/02/2012

4. ### A couple proofs about matrices and vectors?

...a_(1, j) * x_j , Σ(j=1 to n) a_(2, j) * x_j , ..., Σ(j=1 to n) a_(n, j) * x_j) Therefore, f(x) = x₁ Σ(j=1 to n) a_(1, j) * x...

1 Answers · Science & Mathematics · 12/10/2011

5. ### What is geometric mean?

... the n-th root of the product of all n of them: GM(a[1], ..., a[n]) = (∏[j=1,n] a[j])^(1/n) For n = 2, this is GM(a, b) = √(ab...

3 Answers · Science & Mathematics · 15/04/2011

6. ### If A is a fixed nxn matrix, and T(B)=AB, prove that if A is diagonalizable then T is diagonalizable?

...matrix. That is, for any j: a(1, j)b(1, j) + a(2, j)b(2, j) + ... + a(n, j)b(n, j) = 0 But then, all the action happens in the jth column, where...

1 Answers · Science & Mathematics · 11/03/2014

7. ### Prove 4^n = (sum from j=0 to n)(nCj)(3^j)?

...the Binomial Theorem: (a + b)^n = sum(j=0 to n) nCj * a^(n - j) * b^j. If we let a = 1 and b = 3 (a should be 1 to eliminate the n - j exponent...

2 Answers · Science & Mathematics · 07/08/2010

8. ### Math help! I need some help in Algebra? (10 points)?

I'm not very sure, but if none of the other answers on here work, seach on google... "letter equation" or "variable equation" and see what comes up.

3 Answers · Science & Mathematics · 28/09/2009

9. ### Binomial Theorem help please!?

... terms of the binomial expansion of (a + b)^n are C(n,j) * a^(n - j) * b^j Since we want the term for t^8 then n - j = 8. Given n...

3 Answers · Science & Mathematics · 18/08/2009

10. ### PreCalculus - Binomial Theorem: Find the coefficient of x^8 in the expansion (x^2+3)^7?

Well in this case the formula would be (n C n-j)*a^(n-j)*(x^2)^j x^8 = (x^2)^4 so j = 4 n = 7 n - j = 3 a = 3 So the...

2 Answers · Science & Mathematics · 26/07/2009