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  1. ... 3) W = µmgd = 0.44 * 12kg * 9.8m/s² * 2.9m = 150 J It's possible you'll have to give that a negative sign. I consider it understood. 4) remaining KE...

    1 Answers · Science & Mathematics · 07/08/2020

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    2 Answers · Science & Mathematics · 07/08/2020

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    1 Answers · Science & Mathematics · 10/08/2020

  4. ...v = 2.1 m/s 4) W2 = ½ * 4.1kg * (2.1m/s)² = 9.2 J 5) T = W2 / d = 9.2J / 0.83m = 11 N 6) positive (since its KE increases) 7) W1 = ...

    2 Answers · Science & Mathematics · 07/08/2020

  5. a ) Determine the amount of work done. I will ASSUME this means work done on the block by the horizontal force. U = Fd = 150(1.5cos35) = 184 J b) What is its initial potential energy? In reference to what location? If we set the origin...

    2 Answers · Science & Mathematics · 12/08/2020

  6. I'll use a naming convention I think slightly clearer: mass of...36e22/3.844e8} + ½*5534²] E = m * -4.72164e7 J for launch vehicle mass m in kg When the KE is...

    2 Answers · Science & Mathematics · 10/08/2020

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