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  1. One year has 4 quarters,so Mr. Cooper's yearly income of dividends is $0.35*280*4=$392

    3 Answers · Science & Mathematics · 30/07/2008

  2. SE = 120/sqrt(25) = 24 z = ± 50/24 = ± 2.08 to 2 dp P(-2.08 < z < 2.08) = 0.9624 [ D ] <------

    1 Answers · Science & Mathematics · 02/08/2012

  3. P(X < 35,000.0) = P((x - 30,000) / 5,000.0) < (35,000.0 - 30,000) / 5,000.0) = P(Z < 1.00) = 0.8413 P(X > 35,000.0) = 1 - 0.8413 = 0.1587

    2 Answers · Science & Mathematics · 24/04/2007

  4. OK .06x + .07y + .08z = 67,500; x = 3z x + y + z = 1,000,000; substitute in two of the equations .18z + .07y + .08z = 67,500...

    2 Answers · Science & Mathematics · 05/07/2009

  5. ...9y + 10z = 8640000 32z + 9y + 10z = 8640000 42z + 9y = 8640000 4z+y+z = 1000000 5z + y = 1000000 now two equations 42z + 9y...add –45z – 9y = – 1000000 42z + 9y = 8640000 –3z = 784000 with a negative answer, that means the input data is faulty...

    1 Answers · Science & Mathematics · 03/07/2009

  6. 1, 1, 1, 315000 9/100, 1/10, 3/25, 32200 -5/2, 1, 0, 0 Inverse of coefficient matrix times [315000, 32200, 0] 3/2, -25/2, -1/4, 15/4, -125/4, 3/8, -17/4, 175/4, -1/8, Solution: x = 70000; y = 175000; z = 70000

    1 Answers · Science & Mathematics · 14/05/2013

  7. Let x,y, and z be the amount of money borrowed at 8%, 9% and 12% respectively. The whole... money,which is equal to $150,000, is the sum of x,y and z. Thus: x+y+z=150,000 The total amount of interest ($13,300) ...

    3 Answers · Science & Mathematics · 16/07/2013

  8. ...general form for radioactive decay is xe^(-zy) where x is the initial amount of a substance, z is the decay constant, and y is the time elapsed. we can create...

    4 Answers · Science & Mathematics · 24/12/2012

  9. a) You need to find a z-score for 51 pounds and find the area under the curve to the right of that z...5 z = (x - μ)/σ z = (51 - 50)/0.5 z = 1/0.5 z = 2 Look at a z-table to find the area to the right of z = 2. P(z>2) = .0227 This...

    2 Answers · Science & Mathematics · 09/08/2008

  10. ...should be using the t-distribution - treating your t-value as a z-score will give an inflated p-value. Assuming that your t...

    3 Answers · Science & Mathematics · 17/11/2011

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