...a nuclear power station). So the mass is entirely converted into

**energy**, with the formula e=mc^2 you can easily get the amount of**energy**the mass has...4 Answers · Science & Mathematics · 25/06/2013

heat

**energy**= mass x specific heat x change in temp ......... eqn for heating up heat**energy**= heat of fusion x mass .... eqn for melting**energy**to heat up = (207.2)(.0306...1 Answers · Science & Mathematics · 13/06/2008

If the

**energy**/gram is given, the problem is solvable. Or if the type/name...1 Answers · Science & Mathematics · 16/02/2013

...equation 2O₃(g) → 3O₂(g) ΔH(rxn) = -284.6 kJ ( 2g ) ( 1mole O₃ / 48g ) (-284.6 kJ / 2 moles of O₃) = -5...

2 Answers · Science & Mathematics · 05/12/2013

It takes 4.184 Joules to raise a 1g of water 1 degree C. Thus it would take 24 x 4.184 to raise

**2g**of water 12C, or 100.416 Joules of**energy**.1 Answers · Science & Mathematics · 28/05/2012

### If

**2g**of water is initially 250Kelvin, what is the final temperature after 4.5kJ of**energy**is added?... melts at 273K. 273-250=23K change. 23K*

**2g***2.03J/gK=93.38J It takes 334 J/g...1 Answers · Science & Mathematics · 05/04/2008

... Heat of Lead = 0.128J/g/°C. 207. 2g x 0.128J/g/°C x 319°C = 8,460J = 8.460kJ...

1 Answers · Science & Mathematics · 15/04/2008

... Heat of Lead = 0.128J/g/°C. 207. 2g x 0.128J/g/°C x 319°C = 8,460J = 8.460kJ...

1 Answers · Science & Mathematics · 13/04/2008

That is correct. Had they been fired with the same VELOCITY, the heavier bullet would have done more work.

10 Answers · Science & Mathematics · 23/10/2006

So one mole needs +357kj, that would be the mr of Cu(OH)2 which is 97.5g (63.5 + 2(16+1)) Therefore if 97.5g requires 357kj, 10.2 g requires 37.3 kj Hope this helps!

1 Answers · Science & Mathematics · 29/08/2011