**1**3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 994 Answers · Education & Reference · 05/10/2009

...;iostream.h> #include<conio.h> void main() { int i; for(i=

**1**;i<=**100**;i++) { if(i%2==0) { cout<<i<&...4 Answers · Computers & Internet · 06/11/2012

... the same thing then multiply by the number of equations.

**1**+**100**= 101 2+99 = 101 3+98 = 101 4+97 = 101 See the pattern? This will...8 Answers · Science & Mathematics · 30/01/2007

1st

**1**2 3 4 5 6 7 8 9 .................**100**likewise or a pictures in the**numbers**of**1**2 3 .........**100**(SAMLL PICTURES) one two three................hundred i ii iii iv v...1 Answers · Science & Mathematics · 07/09/2006

...can do is exclude all

**numbers**that are even as a result...for (n=3; n<=**100**; n+=2) The most common... divisors:**1**and itself.**To**find all the prime**numbers**...2 Answers · Computers & Internet · 22/05/2010

..., assuming we're talking about integers, "the

**numbers 1**-**100**exclusive" would be 2, 3, 4... 98, 99. Or, are you trying**to**add them? In which case, it would be 101*50, or 5050 Method...3 Answers · Education & Reference · 03/01/2010

sum of first n natural

**numbers**= (**1**/2)n(n+**1**) sum of first**100 numbers**= (**1**/2)(**100**)(101) = 50506 Answers · Science & Mathematics · 18/01/2010

... comment, are random. Chew on those for a while, then move on

**to**the other problems. And there are ALWAYS other ...2 Answers · Computers & Internet · 07/11/2010

Prime

**numbers**between through**1 to 100**is 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97....12 Answers · Science & Mathematics · 16/01/2007

//java statement int x=

**1**; int sum=0; while (x<=**100**) { sum+=x; x++; } System.out.println("sum of whole**numbers**between**1**and**100**is= "+sum);6 Answers · Computers & Internet · 08/03/2007