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  1. Assume a 100 g sample of the gas- 64. 81 g C = 5.396 mol C atoms 13.60 g H = 13.493 mol...mass 0.03435 = 2.57 g / molar mass molar mass = 74.8 Molecular formula = C4 H10 O

    1 Answers · Science & Mathematics · 08/01/2011

  2. ... start with Imperial. :D C - 64. 81 % / 12.01 = 5.396 H - 13.60% / 1.01 = 13.465 O... your imperial equation is C4 H10 O Now Gas Law...

    1 Answers · Science & Mathematics · 15/03/2011

  3. ... some photos: http://upload.wikimedia.org/wikipedia/commons/thumb/c/ c4 /Carbonic-acid-2D.svg/514px-Carbonic-acid-2D.svg.png http://upload.wikimedia.org/wikipedia/commons/thumb/8/ 81 /Carbonic-acid-3D-vdW.png/691px-Carbonic-acid-...

    3 Answers · Science & Mathematics · 22/03/2010

  4. ... gives ratios of C=57.8/12=4. 81 ; H=3.62/1=3.62; O=38.58/16= 2.41 We... good. Dividing we get ratios of C4 , H3, O2 That means we have...

    1 Answers · Science & Mathematics · 16/02/2010

  5. ... C, 2.62 moles H and 4. 81 moles O Divide through by the ... get all whole numbers, multiply by 4 to get C4 H6 O11 = EMPIRICAL FORMULA...

    2 Answers · Science & Mathematics · 15/12/2016

  6. ... chemical equation for (a) the complete combustion of butyric acid, H C4 H7 O2 (I) & 5 O2 (g) -- 4 CO2 (g) & 4 ...

    2 Answers · Science & Mathematics · 03/09/2008

  7. ... number C2 H 1.5 O we multiply by 2 C4 H3O2 ( Molar mass = 83 g/mol) molar mass compound = 52.3 / 0.315 =166...

    1 Answers · Science & Mathematics · 22/10/2008

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